Answer:
The concentration of the acid is about 0.114 M (option E)
Explanation:
Step 1: Data given
Volume of the monoprotic acid = 25.0 mL = 0.025 L
Molarity of the monoprotic acid = ?
Molarity of the NaOH solution = 0.115 M
Volume NaOH = 24.8 mL = 0.0248 L
Step 2: Calculate the concentration
a*Cb * Vb = b * Ca * Va
⇒ a = the coeficient of NaOH = 1
⇒ Cb = the molarity of the acid = TO BE DETERMINED
⇒ Vb = the volume of the acid = 0.025 L
⇒ b = the coefficient of the acid = monoprotic = 1
⇒ Ca = the moalrity of NaOH = 0.115 M
⇒ Va = the volume of NaOH = 0.0248 L
1 * Cb * 0.025 = 1 * 0.115 * 0.0248
0.025 Cb = 0.002852
Cb = 0.11408 M
The concentration of the acid is about 0.114 M
A, radium-228. Alpha radiation is essentially just two protons and two neutrons leaving the atom, causing the atomic number to drop by two (since the protons left) and the mass number to drop by four (since two neutrons and protons left).
The correct answer is Gamma decay. It happens after beta and alpha decay
because what's left after those two can enter a new process of gamma
decay. This releases gamma rays which is a more complex term for the
photons that you mentioned before. These rays can be dangerous for
humans so care not to get caught in them.
I am pretty sure it is 4.002602
Answer:
Molality of the solution = 0.7294 M
Explanation:
Given:
Number of magnesium arsenate = 1.24 moles
Mass of solution = 1.74 kg
Find:
Molality of the solution
Computation:
Molality of the solution = Mole of solute / Mass of solution = 1.74 kg
Molality of the solution = 1.24 / 1.7
Molality of the solution = 0.7294 M
