Answer:
Answer:
step 1:balance skeleton equation the chemical equation:
Zn +HNO3➔Zn(NO3)2+NO+H2O
step 2: identity undergoing oxidation or reduction
here
Zn➔Zn(NO3)2
Zn is oxidized from 0 to 2 in oxidation no.
HNO3➔NO
N is reduced from 5 to 2 in oxidation no
Step 3: calculate change in oxidation no.
change in oxidation no
in Zn=0-2=-2=2
in
N=5-2=3
Step 4: Balance it by doing crisscrossed multiplication
we get;
3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O
step 6:Balance other atoms except H & O
3Zn +2HNO3➔3Zn(NO3)2+2NO+H2O
3Zn +2HNO3+6HNO3➔3Zn(NO3)2+2NO+H2O
finally: balance H
<em><u>3Zn +8HNO3➔3Zn(NO3)2+2NO+4H2O</u></em>
Answer:
65.08 g.
Explanation:
- For the reaction, the balanced equation is:
<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>
2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.
- Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:
<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>
<u><em>Using cross multiplication:</em></u>
2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.
0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.
∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.
<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol
) = <em>65.08 g.</em>
Answer:
Salt water is, A. a mixture
Are u sure this is the right option? Well, antimony can be decomposed. Including octane.
Answer
2.1 x 10 ^23
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