Answer:
806.3g
Explanation:
Given parameters:
Number of moles of silver nitrate = 4.85mol
Unknown:
Mass of silver chromate = ?
Solution:
2AgNO₃ + Na₂CrO₄ → Ag₂CrO₄ + 2NaNO₃
To solve this problem, we work from the known to the unknown;
- The known specie here is AgNO₃ ;
From the balanced chemical equation;
2 moles of AgNO₃ will produce 1 mole of Ag₂CrO₄
4.85 moles of AgNO₃ will produce
= 2.43moles of Ag₂CrO₄
- Mass of silver chromate produced;
mass = number of moles x molar mass
Molar mass of Ag₂CrO₄
Atomic mass of Ag = 107.9g/mol
Cr = 52g/mol
O = 16g/mol
Input the parameters and solve;
Molar mass = 2(107.9) + 52 + 4(16) = 331.8g/mol
So,
Mass of Ag₂CrO₄ = 2.43 x 331.8 = 806.3g
Explanation:
I don't know this answer what Hydrogen Helium lithium
Answer: option B. - A, B, D, E, C, H, F, G is correct using the principle of cross-cutting relationships.
The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts through.
Explanation:
The full sequence of events is:
1. Layer A formed.
2. Layer B formed
3. Layer D formed.
4. Layer E formed
5. After layers A-B-D-E were present, intrusion C cut across all three.
6. Fault H formed, shifting rocks E through A and intrusion C.
7. Weathering and erosion created a layer of soil on top of layer F then G.