Answer:
#1- z = 75
#2- t = 1.33
Step-by-step explanation:
<em>HOPE THIS HELPS!!! </em><em>:)</em>
Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
Answer:
8c - 7r + 10p - 20e
Step-by-step explanation:
Subtract (20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)
(20c + 15r + 75p + 50e) - (12c + 22r + 65p + 70e)
Open bracket
20c + 15r + 75p + 50e - 12c - 22r - 65p - 70e
Collect like terms
= 20c - 12c + 15r - 22r + 75p - 65p + 50e - 70e
= 8c - 7r + 10p - 20e
Answer:
32.44 quilts will be sewn
Step-by-step explanation:
811/25 = 32.44
There are 4.53592 kilograms in 10 lbs.
