<span>Considering that Seth travels with constant speed <span><span>v=<span>dt</span></span><span>v=<span>dt</span></span></span>, then <span><span>v=<span>157.1</span>=<span>x3600</span></span><span>v=<span>157.1</span>=<span>x3600</span></span></span> where <span>xx</span> is the distance traveled in 1 hour. So his velocity would be x miles/hour. By computing <span><span>x=<span><span>3600⋅1</span>57.1</span>=63.047</span><span>x=<span><span>3600⋅1</span>57.1</span>=63.047</span></span>, thus Seth travels at a speed of <span><span>63.047miles/hour</span><span>63.047miles/hour</span></span></span>
Haven’t done this in a while but the first is rational, second is irrational, third is rational, fourth is irrational, fifth is rational, sixth is rational, seventh is irrational
This is just simple Pythagorean’s theorem. a^2 + b^2 = c^2
Number 2:
5^2 + x^2 = 10^2
25 + x^2 = 100
x^2 = 75
x = sqrt 75 = 5*sqrt(3)
Number 3:
4^2 + x^2 = 7^2
16 + x^2 = 49
x^2 = 33
x = sqrt 33
Step-by-step explanation:
∆TSU=∆RSU (SAS).
HENCE,
NONe of the above statement is true.
