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-Dominant- [34]
3 years ago
9

I need help with this problem Someone explain this to me

Mathematics
1 answer:
Anton [14]3 years ago
5 0

Answer:

16.5

Step-by-step explanation:

Look at the relation between the 2 sides that you have measurements for. One is 16cm, the other 24cm. This means that triangle 2 is 1.5 times larger than triangle 1. Multiply the known measurement from tringle 1, 11cm by 1.5 and you get 16.5 cm

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Find the equation of the axis of symmetry for the parabola y = x2 + 2x − 9
Artemon [7]

Answer:

the answer is x=-1

Step-by-step explanation:


5 0
3 years ago
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Solve the system. <br> y= -2x + 1<br><br> y= 2x - 3
Neporo4naja [7]

Equation 1: y = -2x + 1

Equation 2: y = 2x - 3

Since both equations already have y isolated, we are able to simply set the right side of both equations equal to each other. Since we know that the value of y must be the same, we can do this.

-2x + 1 = 2x - 3

1 = 4x - 3

4 = 4x

x = 1

Then, we need to plug our value of x back into either of the original two equations and solve for y. I will be plugging x back into equation 2 above.

y = 2x - 3

y = 2(1) - 3

y = 2 - 3

y = -1

Hope this helps!! :)

5 0
3 years ago
Read 2 more answers
The length of a sticky note measures 77 millimeters.express this length in meters explain your thinking include an equation with
Eva8 [605]

The length of the sticky notes is \bf77\times{10^{-3}}{\text{meter}}.

Further explanation:

Given:

The length of sticky notes is measured as 77 millimeters.

Calculation:

Since 1 meter contains 1000 mm, it can be written as follows:

\begin{aligned}1000{\text{mm}}&\to{\text{1meter}}\\{\text{1mm}}&\to\frac{{\text{1}}}{{1000}}{\text{meter}}\\{\text{1mm}}&\to{10^{-3}}{\text{meter}}\\x\,{\text{mm}}&\to x \times {10^{-3}}{\text{meter}} \\ \end{aligned}

Now, substitute 77 for x in above expression to obtain the length of sticky notes in meter as follows:

77\,{\text{mm}}\to77\times{10^{-3}}{\text{meter}}

Thus, the length of the sticky notes is \bf77\times{10^{-3}}{\text{meter}}.

Learn more:  

1. Which function has an inverse that is also a function? {(–1, –2), (0, 4), (1, 3), (5, 14), (7, 4)} {(–1, 2), (0, 4), (1, 5), (5, 4), (7, 2)} {(–1, 3), (0, 4), (1, 14), (5, 6), (7, 2)} {(–1, 4), (0, 4), (1, 2), (5, 3), (7, 1)}  

brainly.com/question/1632445  

2. A given line has the equation 10x + 2y = −2. what is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)? y = ( )x + 12  

brainly.com/question/1473992  

3. what are the domain and range of the function f(x) = 3x + 5?  

brainly.com/question/3412497  

Answer Details :

Grade: Middle School

Subject: Mathematics

Chapter: linear equation

Keywords:

Millimeters, meter, equation, sticky notes, measurements, length, function, substitution, Mexico, site, direct substitution, elimination, graph, middle term factorization, scientific notation.

3 0
3 years ago
Read 2 more answers
What is the equation of this graphed line?
Arturiano [62]

Answer:

y = -1/3x - 5

Step-by-step explanation:

Use rise over run to find the slope: (y2 - y1) / (x2 - x1)

Plug in the points:

(y2 - y1) / (x2 - x1)

(-7 + 3) / (6 + 6)

-4 / 12

= -1/3

Plug in the slope and a point into y = mx + b, and solve for b:

y = mx + b

-3 = -1/3(-6) + b

-3 = 2 + b

-5 = b

Plug in the slope and b into y = mx + b

y = -1/3x - 5 is the equation of the line

8 0
3 years ago
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XYZ has coordinates X(2, 3), Y(1,4), and Z(8,9). A translation maps X to X'(4,7). What are the coordinates for Y' and Z' for thi
Rashid [163]

Answer:

The coordinates are Y'(x,y) = (3, 8) and Z'(x,y) = (10, 13).

Step-by-step explanation:

First, we have to derive an expression for translation under the assumption that each point of XYZ experiments the same translation. Vectorially speaking, translation from X to X' is defined by:

X'(x,y) = X(x,y) + T(x,y) (1)

Where T(x,y) is the vector translation.

If we know that X(x,y) = (2,3) and X'(x,y) = (4,7), then the vector translation is:

T(x,y) = X'(x,y)-X(x,y)

T(x,y) = (4,7) - (2,3)

T(x,y) = (2, 4)

Then, we determine the coordinates for Y' and Z':

Y'(x,y) = Y(x,y) + T(x,y)

Y'(x,y) = (1,4) + (2,4)

Y'(x,y) = (3, 8)

Z'(x,y) = Z(x,y) + T(x,y)

Z'(x,y) =(8,9) + (2,4)

Z'(x,y) = (10, 13)

The coordinates are Y'(x,y) = (3, 8) and Z'(x,y) = (10, 13).

7 0
3 years ago
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