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muminat
2 years ago
5

Shane bought lunch for $5.38 and a shirt for $15.95. He then used the rest of his money to buy a book. He spent a total of $38.1

2. How much money did Shane spend on the book?
$10.57

$16.79

$22.17

$32.74
Mathematics
1 answer:
barxatty [35]2 years ago
7 0
You add $5.38 & $15.95, which equals $21.33. Then subtract $21.33 from $38.12. Your answer is $16.79. That's how much Shane spent on the book.
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If two ppl working at 7.00 per hour work 8 hours making trays that cost 35.00 each if it cost 14.00 to make the trays how many w
sasho [114]

Answer:

They have to make 6 trays to cover the cost including labor.

Step-by-step explanation:

Given:

Number of labor =2

Cost per hour of labor =7.00

Number of hours they work = 8

Selling cost of each trays =35.00

making cost of each tray = 14.00

We need to find the number of trays they to make to cover the cost including the labor.

Solution:

Let the number of trays be 'x'.

First we will will find the Total cost of labor.

Total cost of labor is equal to Number of labor multiplied by Cost per hour of labor multiplied by Number of hours they work.

framing in equation form we get;

Total cost of labor  = 2\times 7\times8 =112.00

Now we can say that;

Selling price of each tray multiplied number of trays equal to Making cost of each trays multiplied by number of tray plus Cost of labor.

framing in equation form we get;

112+14x=35x

Combining like terms we get;

112= 35x-14x\\\\112=21x

Dividing both side by 21 using division property of equality we get;

\frac{112}{21} = \frac{21x}{21}\\\\5.33=x

Hence They have to make 6 trays to cover the cost including labor.

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3 years ago
A gold coin appreciated in value from $200.00 to $475.00 in 6 years. Find the yearly rate of appreciation. Show or explain all w
Travka [436]

Answer:

16%

Step-by-step explanation:

To solve this we are using the standard growth equation:

y=a(1+b)^x

Were

y is the final value after x years

a is the initial value

b is the growth factor (yearly rate of appreciation in our case) in decimal form

x is the time in years

We know from our problem that gold coin appreciated in value from $200.00 to $475.00 in 6 years, so y=475, a=200, and x=6.

Let's replace the values in our equation and solve for b:

y=a(1+b)^x

475=200(1+b)^6

\frac{475}{200} =(1+b)^6

2.375=(1+b)^6

\sqrt[6]{2.375} =\sqrt[6]{(1+b)^6}

1+b=\sqrt[6]{2.375}

b=\sqrt[6]{2.375}-1

b=0.155

which rounds to

b=0.16

Since our appreciation rate is in decimal form, we need to multiply it by 100% to express it as percentage:

0.16*100% = 16%

We can conclude that the yearly appreciation rate of our gold coin is approximately 16%

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2 years ago
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Answer:

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Step-by-step explanation:

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