Ask question

Ask question

All categories

2 years ago

13

1. Find the value of x in the equation √ x + 5 = √ x + 45. A. 16 B. 4 C. 1 D. 2

2 answers:

Nimfa-mama [501]2 years ago

8 0

Answer: Option 'A' is correct.

Step-by-step explanation:

Since we have given that

$\sqrt{x}+5=\sqrt{x+45}$

We need to find the value of x in the above equation:

$\sqrt{x}+5=\sqrt{x+45}\\\\\text{ On squaring both sides , we get}\\\\(\sqrt{x}+5)^2=x+45\\\\x+5\sqrt{x}+25=x+45\\\\5\sqrt{x}+25=45\\\\5\sqrt{x}=45-25=20\\\\\sqrt{x}=\frac{20}{5}\\\\\sqrt{x}=4\\\\\text{ on squaring both sides}\\\\x=4^2=16$

Therefore, the value of x = 16

Hence, Option 'A' is correct.

Korvikt [17]2 years ago

7 0

I think you mean
sqrt x + 5 = sqrt (x+45)

if you plug in x = 4,
left side = sqrt 4 + 5 = 2+ 5 = 7

right side = sqrt (4+45) = sqrt 49 = 7

so the answer is x = 4 :)

You might be interested in

Nathan can paint 2/9 of the fence in one day select all statements that correctly describes the process of finding how long it w

storchak [24]

Two and two-thirds of a day, but you should say three days.

8 0

3 years ago

What is the 4th term of the linear sequence below?<br> -9,-5, -1,3,7,...

Anton [14]

Answer:

The 4th term of the linear sequence = 3

Step-by-step explanation:

First term, a = -9

Common difference, d = -5 - (-9)

= -5 + 9

= 4

d = 4

The 4th term of the linear sequence = a + (n - 1)d

where,

n = 4

a + (n - 1)d

= -9 + (4 - 1)4

= -9 + (3)4

= -9 + 12

= 3

The 4th term of the linear sequence = 3

7 0

2 years ago

Can a function ever have 2 y-<br> intercepts?

Sauron [17]

Answer:

yes I think I'm new to this but I think that's a yes

7 0

1 year ago

$12 meal; 4.5% tax find total cost to the nearest cent

Lemur [1.5K]

Answer:

12.54

Step-by-step explanation:

just multiply 12×0.045 and add the 12.

I hope and this helps.

Have a good day.

Good luck

8 0

2 years ago

Read 2 more answers

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

$y = -16x^2 + 177x + 98$

It hits the ground when $y = 0$ , so we have to find x for which $y = 0$ , which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$y = -16x^2 + 177x + 98$

$-16x^2 + 177x + 98 = 0$

So

$a = -16, b = 177, c = 98$

$\bigtriangleup = 177^{2} - 4(-16)(98) = 37601$

$x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53$

$x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59$

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

4 0

2 years ago