Question

Calculate the magnitude of the electric field at one corner of a square 1.10 m on a side if the other three corners are occupied by 4.05×10−6 C charges. What is the direction of the electric field?

Answer 1

The direction of magnetic field is south-east and the magnitude is

$23.66$ × $10^{3} N/C$.

Here, the magnitude of CD and BC will be cancelled, as they both are in the opposite direction and equal to each other.
the magnitude, towards the diagonal AC will result in CP, which is the direction of the electric field.

magnitude of electric field can be defined as :- The force per charge on the test charge is a straight forward way to define the size of the electric field.

To find the magnitude of the electric field use the formula

$E = kq/ r^{2}$

inserting the values,

$E = 9. 10^{9}$ × $4.05$ × $10^{-6} / 1.1 \sqrt{2}$

$E= 36.45$ × $10^{3}$ / $1.54$

$E = 23.66$ × $10^{3}$ N/C

Learn more about calculating magnitude of the electric field at one corner here:-

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