How old is donald trumpp------ i NEED answer .

ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements.

vekshin1

Answer:

The answer is 500

Explanation:

6 0

2 years ago

The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Colum

TEA [102]

"The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis."

typical plot is speed or velocity on the y-axis n time on the x-axis so the ans is Column 1 should be titled “Time,” and Column 2 should be titled “Velocity.”

7 0

3 years ago

Read 2 more answers

How many kj of heat are needed to completely melt 144 g of titanium metal, given that the metal is at its melting point? the hea

Elina [12.6K]

Given, mass of titanium metal = 144 g

Heat of fusion of titanium metal= 18.7 J/g

Heat of fusion is the amount of heat energy needed to change the state of one gram of a substance from solid to liquid or vice-versa.

Thus, 18.7 J of heat is needed to melt one gram of titanium metal.

Therefore, heat needed to melt 144 g of titanium metal = 18.7×144

= 2692.8 J

8 0

3 years ago

Two taut strings of identical mass and length are stretched with their ends fixed, but the tension in one string is 1.10 times g

ollegr [7]

Answer:

The beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz

Explanation:

Given;

velocity of wave on the string with lower tension, v₁ = 35.2 m/s

the fundamental frequency of the string, F₁ = 258 Hz

velocity of wave on the string with greater tension;

$v_1 = \sqrt{\frac{T_1}{\mu }$

where;

v₁ is the velocity of wave on the string with lower tension

T₁ is tension on the string

μ is mass per unit length

$v_1 = \sqrt{\frac{T_1}{\mu} } \\\\v_1^2 = \frac{T_1}{\mu} \\\\\mu = \frac{T_1}{v_1^2} \\\\ \frac{T_1}{v_1^2} = \frac{T_2}{v_2^2}\\\\v_2^2 = \frac{T_2v_1^2}{T_1}$

Where;

T₁ lower tension

T₂ greater tension

v₁ velocity of wave in string with lower tension

v₂ velocity of wave in string with greater tension

From the given question;

T₂ = 1.1 T₁

$v_2^2 = \frac{T_2v_1^2}{T_1} \\\\v_2 = \sqrt{\frac{T_2v_1^2}{T_1}} \\\\v_2 = \sqrt{\frac{1.1T_1*(35.2)^2}{T_1}}\\\\v_2 = \sqrt{1.1(35.2)^2} = 36.92 \ m/s$

Fundamental frequency of wave on the string with greater tension;

$f = \frac{v}{2l} \\\\2l = \frac{v}{f} \\\\thus, \frac{v_1}{f_1} =\frac{v_2}{f_2} \\\\f_2 = \frac{f_1v_2}{v_1} \\\\f_2 =\frac{258*36.92}{35.2} \\\\f_2 = 270.6 \ Hz$

Beat frequency = F₂ - F₁

= 270.6 - 258

= 12.6 Hz

Therefore, the beat frequency when each string is vibrating at its fundamental frequency is 12.6 Hz

6 0

3 years ago

g A beam of light incident on a smooth flat mirror at an angle of 25o relative to the surface normal of the mirror. What is the

WINSTONCH [101]

To solve this problem we will resort to the concept of angle of incidence and refraction.

Since it is a reflection on a mirror, the angle provided for refraction will be equal to that of the incidence, that is, 25 °

The angle of reflation is always perpendicular to the surface so it is necessary to find the angle with respect to it.

$\theta = 90-25$

$\theta = 65\°$

Therefore the angle of the reflected beam of light made with the surface normal is 65°

5 0

3 years ago