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Fudgin [204]
3 years ago
14

HELP I RLLY NEED HELP WITH THIS PLEASE HELP ME WHAT IS PHYSICAL SCIENCE ANYBODY???

Physics
1 answer:
Paul [167]3 years ago
7 0

The sciences concerned with the study of inanimate natural objects, including physics, chemistry, astronomy, and related subjects.

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I need help ! if anyone answers this its worth 40 points please help !!
Sliva [168]
Double displacement...I think
3 0
3 years ago
A solid metal ball and a hollow plastic ball of the same external radius are released from rest in a large vacuum chamber. When
S_A_V [24]

Answer:

time of fall and the final velocity

Explanation:

the mass of solid ball is more than the mass of hollow ball.

According to the third equation of motion

v² = u² + 2gh

As the final velocity v does not depend on the mass of the object, so the final velocity of both the ball is same.

According to the first equation of motion

v = u + gt

As v is same for both the balls, the time is also same for both the balls.

So, they both have same time of fall and final velocity.

5 0
3 years ago
How could you have collected your data in different ways that may have more accurately identified the Seymouria?
Pepsi [2]

Answer:accurate indicators of education status and trends; and report timely, useful, and high ... Postsecondary Education Data Collection and Exchange ... coordinate data definitions and surveys on a national basis to achieve greater ... Example: Faculty is a term that is defined in many ways; it can include instructional faculty,.

Explanation:

8 0
3 years ago
At 600.0 k the rate constant is 6.1× 10–8 s–1. what is the value of the rate constant at 785.0 k?
photoshop1234 [79]
Missing details. Complete text is:"The following reaction has an activation energy of 262 kJ/mol:
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
\ln( \frac{K_2}{K_1} ) =  \frac{Ea}{R} ( \frac{1}{T_1}- \frac{1}{T_2}  )
where K are the reaction rates, Ea is the activation energy, R=8.314 J/mol*K and T are the temperatures. Using T1=600 K and T2=785 K, and Ea=262 kJ/mol = 262000 J/mol, on the right side of the equation we have
\frac{Ea}{R}( \frac{1}{T_1}- \frac{1}{T_2}  )=12.38
And so
\ln( \frac{K_2}{K_1})=12.38
And using K_1=6.1\cdot 10^{-8} s^{-1} , we find K2:
K_2=K_1 e^{12.38}=0.0145 s^{-1}


5 0
3 years ago
A student moves a horseshoe magnet by hand across a tabletop to varying distances from an electromagnet, as shown in the diagram
Sloan [31]

The closer together they are the harder it is to hold on to because the magnetic field is stronger as it gets closer.


Answer:

D. The electromagnet's magnetic field is stronger close to it than far from it.​

4 0
2 years ago
Read 2 more answers
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