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Fudgin [204]
3 years ago
14

HELP I RLLY NEED HELP WITH THIS PLEASE HELP ME WHAT IS PHYSICAL SCIENCE ANYBODY???

Physics
1 answer:
Paul [167]3 years ago
7 0

The sciences concerned with the study of inanimate natural objects, including physics, chemistry, astronomy, and related subjects.

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The electric potential, when measured at a point equidistant from two particles that have charges equal in magnitude but of oppo
Reika [66]

Answer:

C) equal to zero

Explanation:

Electric potential is calculated by multiplying constant and charge, then dividing it by distance. The location that we want to measure is equidistant from two particles, mean that the distance from both particles is the same(r2=r1). The charges of the particle have equal strength of magnitude but the opposite sign(q2=-q1). The resultant will be:V = kq/r

ΔV= V1 + V2= kq1/r1 + kq2/r2

ΔV= V1 + V2= kq1/r1 + k(-q1)/(r)1

ΔV= kq1/r1 - kq1/r1

ΔV=0

The electric potential equal to zero

4 0
4 years ago
An 870 N firefighter, F_ff, stands on a ladder that is 8.00 m long and has a weight of 355 N, F_ladder. The weight of the ladder
castortr0y [4]

Answer:

Explanation:

Weight of the ladder is 355N

WL = 355N

The weight of the ladder acts at center of the ladder I.e at 4m from the bottom

Weight of firefighters is 870N

Wf = 870N

The fire fighter is at 6.3m from the bottom of the ladder.

N1 is the normal force exerted  by the wall

N2 is the normal force exerted  by the ground

Using Newton law

Check attachment

ΣFy = 0, since body is in equilibrium

N₂ - WL - Wf = 0

N₂ = WL + Wf

N₂ = 870 + 355

N₂ = 1225 N

This the normal force exerted by the ground on the wall.

Now to get N₁, let take moment about point A

So, before we take the moment we need to make sure that the forces are perpendicular to the plane(ladder), we need to resolve the weight of the ladder, firefighter and the normal of the wall to be perpendicular to the plane.

ΣMa = 0

Clockwise moment is equal to anti-clockwise moment

Moment Is the produce of force and perpendicular distance.

M = F×r

So,

WL•Cos50 × 4 + Wf•Cos50 × 6.3 —N₁•Sin50 × 8 = 0

355•Cos50 × 4 + 870•Cos50 × 6.3 =

N₁•Sin50 × 8

1825.52 + 3523.12 = 6.13N₁

6.13N₁ = 5348.64

N₁ = 5348.64/6.13

N₁ = 872.54 N.

The normal force exerted by the wall is 872.54N

5 0
3 years ago
When riding on a plane, passengers not only move through space but they move through______as well.
Ludmilka [50]

Answer:

Explanation: the atmosphere

8 0
4 years ago
Read 2 more answers
If you ride an elevator moving forward with a constant speed, is your apparent weight same,greater than or less than your weight
wlad13 [49]
If the elevator's speed is constant (in ANY direction) and you can't see out of it, then there's NO measurement you can make inside that will tell you that it's moving. Any weight you measure is normal.
6 0
3 years ago
What is umax,c, the value of the maximum energy stored in the capacitor during one cycle?
TiliK225 [7]

1) 0.266 H

2) 0.040 J

3) 0.308\Omega

Explanation:

The diagram of the circuit is missing: find it in attachment.

1) What is L, the value of the inductance of the circuit?

For an RLC circuit, the resonant angular frequency is given by:

\omega=\frac{1}{\sqrt{LC}}

where

L is the inductance of the circuit

C is the capacitance of the circuit

In this problem, we have:

\omega=164 rad/s is the angular frequency of the generator, at which the circuit is in resonance

C=140 \mu F = 140\cdot 10^{-6}F is the capacitance

Therefore, solving for L, we find the inductance of the circuit:

L=\frac{1}{\omega^2 C}=\frac{1}{(164)^2(140\cdot 10^{-6})}=0.266 H

2) What is umax,c, the value of the maximum energy stored in the capacitor during one cycle

The maximum energy stored in a capacitor is given by the equation

U=\frac{1}{2}CV^2

where

C is the capacitance of the capacitor

V is the maximum potential difference across the capacitor

Here we have:

C=140 \mu F = 140\cdot 10^{-6}F is the capacitance

V=24 V is the maximum voltage across the capacitor, which is the emf of the generator

Substituting, we find:

U=\frac{1}{2}(140\cdot 10^{-6})(24)^2=0.040 J

3) What is R, the value of the resistance of the circuit?

Here we want to find the resistance of the circuit.

The resistance of the circuit can be found by using Ohm's Law:

V=RI

where

V is the maximum voltage

R is the resistance

I is the maximum current

Here we have:

V = 24 V is the maximum voltage provided by the generator

I = 0.78 A is the maximum current in the circuit

Solving for R, we find the resistance:

R=\frac{V}{I}=\frac{0.24}{0.78}=0.308\Omega

6 0
4 years ago
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