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LuckyWell [14K]
2 years ago
14

Identify whether each cell is prokaryotic or eukaryotic

Biology
1 answer:
GalinKa [24]2 years ago
8 0
Plant And Animal Cells Are Eukaryotic.

Prokaryotic Are Single Cells
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In the following table, label each statement as true (T) or false (F). If the statement is false, rewrite it so that it is true.
iren [92.7K]
1) False. Scientists may predict something but realize a difference soon after before the test, so they could definitely change the hypothesis if they want. It’s only AFTER the experiment they cannot. Because a hypothesis is like a “guess” as to what’s going to happen, right?

2) False. A hypothesis can’t be “valid” because it’s literally a prediction.

3) True. Especially if you’re doing a chemistry lab, it’s really important things are done in order or else the product might result as something else you were expecting, or can be very dANGEROUS

4) True. The conclusion must be based on data because it’s the observation that was seen.

Hope this helps!! I could have answered in short form but I just wanted to make them understandable:)
7 0
3 years ago
Are Viruses are smaller than the hosts they infect
Alexus [3.1K]

Answer:

Yes, viruses are super small. It is also smaller than bacteria. So you wouldn't notice anything.

3 0
3 years ago
Read 2 more answers
small group of 100 people decide to isolate themselves from the world and move to a small and remote deserted island. Out of thi
irina [24]

Answer:

Frequency of p = 0.684

Frequency of p = 0.316

Number of individuals with homozygous dominant (AA) = 47

Number of individuals with heterozygous (Aa)= 43

Number of individuals with homozygous recessive (aa) = 10

Explanation:

Out of 100 people, 10 have albino skin (aa)

So, the frequency of homozygous recessive individuals (q^{2}) is \frac{10}{100} = 0.1

Now, q will be

= \sqrt{q^{2} } = \sqrt{0.1} \\= 0.316

As per Hardy Weinberg's equation -

p + q = 1

Substituting the value of q in above equation, we get -

p + 0.316 = 1p = 1 -0.316\\p = 0.684

Now the frequency of homozygous dominant (AA) will be

p^{2} = 0.684^{2} \\= 0.467

Hence, out of 100 people 0.467 * 100 = 46.7 or 47 people are homozygous dominant (AA)

Like wise out of 100 people 0.1 * 100 = 10 people are homozygous recessive (aa)

As per As per Hardy Weinberg's equation-

p^{2} + q^{2} + 2pq = 1\\

Substituting the values in above equation, we get -

0.467 + 0.316 + 2pq = 1\\2pq = 1 -( 0.467+ 0.1)\\2pq = 0.433

So, out of 100 people 0.433 * 100 = 43.3 or 43 people are heterozygous (Aa)

7 0
3 years ago
Explain how a rise in carbon dioxide concentration in the atmosphere can decrease biodiversity.​
Zolol [24]
Elevated carbon dioxide levels may mitigate losses of biodiversity from nitrogen pollution. ... Rising levels of carbon dioxide may overheat the planet and cause other environmental problems, but fears that rising carbon dioxide levels could directly reduce plant biodiversity can be allayed, according to a new study.
4 0
2 years ago
The photosynthetic dinoflagellates called zooxanthellae have a _______________ relationship with the corals in which they live.
vazorg [7]

Answer:

The photosynthetic dinoflagellates called zooxanthellae have a MUTUALISTIC relationship with the corals in which they live.

Explanation:

The relationship that exist between dinoflagellates and corals is simply a symbiotic or mutualistic relationship which entails both organisms benefits from each other.

6 0
3 years ago
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