Stephanie gets on her bike and rides for 3 hours. She rides at an average speed of 12.5 km per

1 answer:

8 0

Stephanie rode the bike with an speed of 37.5 km. If she ride the bude and the average speed for her is 12.5 km per hour, multiply 12.5 with how much hour to get the answer. 12.5x3=37.5. This means that Stephanime rode her bike and got a speed of 37.5 km.

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0.4(5x-15)=2.5(x+3) what is the value of x?

stiv31 [10]

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Candy has to paint a fence if she can paint 2/3 of each section in 1/2 and hour and there are 9 sections how long will it take h

aev [14]

Do you mean half an hour because if she can paint 2/3 of each section in half an hour, it would take her 3 hours to paint all 9 sections. I hope this is correct.

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3 years ago

A company will make a cereal box with whole number dimensions and a volume of 100 cubic centimeters. if carboard cost $0.05 per

Lelu [443]

Possible dimension of a box with a volume of 100 cubic cm
10 x 10 x 1 = 100
10 x 5 x 2 = 100
5 x 5 x 4 = 100

Surface area:
10 x 10 x 1 dimensions:
10 x 10 = 100 x 2 = 200 sq.cm
10 x 1 = 10 x 4 = 40 sq. cm
240 sq. cm * $0.05 / 100 sq.cm = $0.12 per box
0.12 per box * 100 boxes = $12

10 x 5 x 2 dimension
10 x 5 = 50 x 2 = 100 sq. cm
10 x 2 = 20 x 2 = 40 sq. cm
5 x 2 = 10 x 2 = 20 sq. cm
160 sq. cm * $0.05/100 sq. cm = $0. 08 per box
0.08 per box * 100 boxes = $8

5 x 5 x 4 dimension
5 x 5 = 25 x 2 = 50 sq. cm
5 x 4 = 20 x 4 = 80 sq. cm
130 sq. cm * $0.05/100 sq. cm = $0.065 per box
0.065 per box * 100 boxes = $6.50

The best dimension to use to have the least cost to make 100 boxes is 5 x 5 x 4. It only costs $6.50 to make 100 boxes.

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3 years ago

If the maximum acceleration that is tolerable for passengers in a subway train is 1.74 m/s2 and subway stations are located 930

Free_Kalibri [48]

Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.

Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by
$s=ut+ \frac{1}{2} at^2$

But, we assume that the train accelerates from rest, thus
$s=\frac{1}{2} at^2 \\ \\ \Rightarrow465=\frac{1}{2}(1.74)t^2 \\ \\ \Rightarrow t^2=534.48 \\ \\ \Rightarrow t=\sqrt{534.48}=23.12$

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).

Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.

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3 years ago

For reviewing purposes

sergeinik [125]

Answer:

(25-16)/9=

=9/9=1 because 5^2 is 25 and 3^2 is 9 (5x5)/(3x3)

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2 years ago