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defon
2 years ago
10

A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr.

The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively. What is the partial pressure in torr of the carbon dioxide in the mixture
Chemistry
1 answer:
AlekseyPX2 years ago
6 0

A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

<h3>What is Dalton's Law of Partial Pressure ?</h3>

Dalton's Law of partial pressure states that the total pressure exerted by non reacting gaseous mixture at a constant temperature and given volume is equal to the sum of partial pressure of all gases.

It is expressed as:

P_{A} = X_{A} P_{T}

where,

P_{A} = Partial pressure of gas A

X_{A} = Mole fraction of gas A

P_{T} = Total pressure

Mole Fraction of Nitrogen

= \frac{930}{930 + 850}

= 0.52

Mole Fraction of Oxygen

= \frac{850}{850 + 930}

= 0.47

Now,

Mole fraction of nitrogen + Mole fraction of oxygen + Mole fraction of carbon dioxide = 1

⇒ 0.52 + 0.47 + Mole fraction of carbon dioxide = 1

⇒ 0.99 + Mole fraction of carbon dioxide = 1

⇒ Mole fraction of carbon dioxide = 1 - 0.99

⇒ Mole fraction of carbon dioxide = 0.01

Now put the value in above expression we get

P_{A} = X_{A} P_{T}

     = 0.01 × 2710

     = 27.1 torr

Thus from the above conclusion we can say that A steel cylinder contains a mixture of nitrogen, oxygen, and carbon dioxide gases. The total pressure in the tank is 2710 torr. The pressure exerted by the nitrogen and oxygen is 930 and 850 torr, respectively.  27.1 torr is the partial pressure of the carbon dioxide in the mixture.

Learn more about the Dalton's Law here: brainly.com/question/14119417

#SPJ4

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Diazomethane has the following composition by mass: 28.57% C, 4.80% H, and 66.64% N. The molar mass of diazomethane is 42.04 g/m
Alex777 [14]

Answer:

CH2N2

Explanation:

To find the molecular formula, we must first find the empirical formula as follows:

28.57% C - 28.57g of Carbon

4.80% H - 4.80g of Hydrogen

66.64% N - 66.64g of Nitrogen

Next, we convert this mass values to mole by dividing by their respective atomic mass.

C = 28.57/12 = 2.38mol

H = 4.80/1 = 4.80mol

N = 66.64/14 = 4.76mol

Next, we divide each mole value by the smallest mole value (2.38mol)

C = 2.38mol ÷ 2.38 = 1

H = 4.80mol ÷ 2.38 = 2.01

N = 4.76mol ÷ 2.38 = 2

The empirical ratio of C, H and N is therefore 1:2:2. Hence, the empirical formula is CH2N2

To calculate the molecular formula;

(CH2N2)n = 42.04 g/mol

{12 + 1(2) + 14(2)}n = 42.04

{12 + 2 + 28}n = 42.04

{42}n = 42.04

n = 42.04/42

n = 1.00009

Since n = 1, molecular formula is CH2N2

8 0
3 years ago
A syringe contains 56.05 mL of gas at 315.1 K. What volume will that gas occupy if the temperature is increased to 380.5 K?
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This is one of the ideal gas laws. Presumably the pressure remains the same so it is not part of the givens.

Formula

V / T = V1 / T1

Givens

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Solution

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0.1779 = x / 380.5                        Multiply both sides by 380.5

0.1779 * 380.5 = 380.5x/380.5

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