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kicyunya [14]
2 years ago
6

first sequence: 3 8 13 18 23 second sequence: -2 4 10 16 . find the TWO numbers that are in both number sequences.​

Mathematics
1 answer:
azamat2 years ago
6 0

a(n) = 3 + 5n

b(n) =  - 2 + 6n

a(n) = b(n) \\ 3 + 5n =  - 2 + 6n \\ 5 = n \\ n = 5 \: (6th \: term)

a(5) \: or \: b(5) = 3 + 5(5) = 28

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52.42

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3 years ago
What is the solution to the system of equations 2x+y=2 and y= -2x-2?
finlep [7]

Answer:

NO SOLUTION

Step-by-step explanation:

Solve this system by substitution:

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3 years ago
Olivia read a book. She started on page 20 and each minute she read 3 minutes. Let g(n) be the page Olivia was on at the beginni
miskamm [114]
If you mean each minute she read 3 pages.



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4 0
3 years ago
Read 2 more answers
I will give a brainlest, i promise, please help me with this.​
valkas [14]

Answer:

1) b and m

2) m∠8=m∠6

3) 160°

4)x=60°

Step-by-step explanation:

1) all straight lines sum to 180°

subtract the angles given from 180°

the other angle for b is 25°, while the other angle for m is 155°

so we can see that the angles for both lines are the same, hence they are parallel.

2) ∠8 should be the same as ∠6, ∠10 should be the same as ∠3, ∠7 same as ∠5 and ∠9 same as ∠4

in the options we are only given '∠8 should be the same as ∠6' as the correct answer, so we take that.

3) from the image we can see that both horizontal lines are parallel to each other, so both angles on the lines should be same, so ∠CET would be (2x-16)°

(2x-16)°+(7x+20)°=180°

we get x=20(nearest whole number)

∠CED=7x+20=7(20)+20=160°

4) since we need to show that they are parallel,

(2x+30)°=(4x-90)°

2x-4x=-90-30

-2x=-120

x=60

we then plug the x value into the two equations, in which we get 150° for both the angles [2(60)+30=4(60)-90] ⇒ (150=150)

I hope u understand it the way I put it.

8 0
3 years ago
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