50 might be the answer because 12÷6=2 so I just multiplied 15×2 and that equaled my answer, 50
Answer: -2/3
3-(-1) over
-2-4
This equals 4/-6 which reduces to -2/3
Answer:
t12= -8
Step-by-step explanation:
t3
a+2d=10 (1)
t10
a+9d=-4. (2)
From (1)
a=10-2d. (3)
Sub into (3) into equ (2)
a+9d=-4
10-2d+9d=-4
10+7d=-4
7d=-4-10
7d=-14
Divide both sides by 7
d=-14/7
d= -2
10=a+2d
10=a+2(-2)
10=a-4
10+4=a
14=a
a=14
t12=a+11d
= 14+11(-2)
=14-22
= -8
t12= -8
Answer:
152 lies between two consecutive integers 151 and 153.
Step-by-step explanation:
Let n be the given integer.
The predecessor of any integer n is given by n-1.
Similarly the successor of an integer n is given by n+1.
For example: Let n be 100
Then its predecessor is 100-1 = 99
Its successor is 100+1 = 101
In the given question, n=152.
Predecessor of 152 = 152 - 1 = 151
Successor of 152 = 152 + 1 = 153
So 152 lies between two successive integers 151 and 153.
