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Artemon [7]
2 years ago
8

These days people use plastic to pay for everything. " What does this synecdoche mean in this question?

Mathematics
2 answers:
GrogVix [38]2 years ago
8 0

Answer:

Synecdoche means in which a part of something is substituted for the whole (as hired hand for "worker")

faust18 [17]2 years ago
4 0

Answer:

ospe4mhe is taht he iaoe

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What set of transformations are applied to parallelogram ABCD to create A'B'C'D'?
denpristay [2]

Answer:

Reflected over the x-axis and rotated 90° counterclockwise

Step-by-step explanation:

3 0
3 years ago
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What is the result of dividing 2x^3+6x^2+6x+2 by x+1 ?<br><br> PLEASE HELP, WILL GIVE 5 RATING
Oduvanchick [21]

2x² + 4x + 2

using long division to obtain the quotient


8 0
3 years ago
What is 37 years converted into hours?
natta225 [31]
There are 24 hrs in a day, and there are 365 days in an year

first step: multiply years with days

37 x 365 = 13505 days in all

second step: multiply days with hrs

13505 x 24 = 324120 hrs

your total is 324120 hrs

hope this helps
6 0
3 years ago
Read 2 more answers
A bookshelf sits on top of a large desk. Together, their height is 6.75 feet. The difference between their heights is 1.85 feet.
slavikrds [6]

Answer: 4.9

Step-by-step explanation:

8 0
2 years ago
38. Evaluate f (3x +4y)dx + (2x --3y)dy where C, a circle of radius two with center at the origin of the xy
lina2011 [118]

It looks like the integral is

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy

where <em>C</em> is the circle of radius 2 centered at the origin.

You can compute the line integral directly by parameterizing <em>C</em>. Let <em>x</em> = 2 cos(<em>t</em> ) and <em>y</em> = 2 sin(<em>t</em> ), with 0 ≤ <em>t</em> ≤ 2<em>π</em>. Then

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \int_0^{2\pi} \left((3x(t)+4y(t))\dfrac{\mathrm dx}{\mathrm dt} + (2x(t)-3y(t))\frac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt \\\\ = \int_0^{2\pi} \big((6\cos(t)+8\sin(t))(-2\sin(t)) + (4\cos(t)-6\sin(t))(2\cos(t))\big)\,\mathrm dt \\\\ = \int_0^{2\pi} (12\cos^2(t)-12\sin^2(t)-24\cos(t)\sin(t)-4)\,\mathrm dt \\\\ = 4 \int_0^{2\pi} (3\cos(2t)-3\sin(2t)-1)\,\mathrm dt = \boxed{-8\pi}

Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on <em>C</em> nor in the region bounded by <em>C</em>, so

\displaystyle \int_C (3x+4y)\,\mathrm dx + (2x-3y)\,\mathrm dy = \iint_D\frac{\partial(2x-3y)}{\partial x}-\frac{\partial(3x+4y)}{\partial y}\,\mathrm dx\,\mathrm dy = -2\iint_D\mathrm dx\,\mathrm dy

where <em>D</em> is the interior of <em>C</em>, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: -2\times \pi\times2^2 = -8\pi.

3 0
2 years ago
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