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8090 [49]
2 years ago
13

What are the first five terms in the recursive sequence defined by the following?

Mathematics
1 answer:
kolezko [41]2 years ago
5 0

The first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

<h3>Recursive function</h3>

Given the nth term of a recursive expression shown below

an =an-1 - 1.4

where

an-1 is the preceding term

a1 is the first term

an is the nth term

an-1 is

Given the following

a1 = 0

For the second term a2

a2 = 0 - 1.4

a2 = -1.4

For the third term a3

a3 = -1.4 - 1.4

a3 = -2.8

For the fourth term a4

a4 = -2.8 - 1.4

a4 = -4.2

For the fifth term a2

a5 = -4.2 - 1.4

a5 = -5.6

Hence the first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

Learn more on recursive function here: brainly.com/question/489759

#SPJ1

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If s(x) = x-7 and f(x) = 4x? – X+3, which expression is equivalent to (tos)(x)?
lesya692 [45]

Answer:

4(x-7)^2-(x-7)+3 (Assuming t is f)

Step-by-step explanation:

Let s(x)=x-7 and t(x)=4x^2-x+3 .

(t o s)(x)=t(s(x))=t(x-7)

Before I continue this means replace the orginal x in t with x-7.

This will then give you

4(x-7)^2-(x-7)+3

4 0
3 years ago
Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to
ra1l [238]

Answer:

The  confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

  The  sample size is n = 41

   

For a 95% confidence the level of significance is  \alpha  = [100 - 95]\% =  0.05 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }=  1.96

For a 90% confidence the level of significance is  \alpha  = [100 - 90]\% =  0.10 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }=  1.645

So we see with decreasing confidence level the critical value  decrease

Now the margin of error is mathematically represented as

         E =  Z_{\frac{\alpha }{2} } *  \frac{s}{\sqrt{n} }

given that other values are constant and only Z_{\frac{\alpha }{2} } is varying we have that

         E\ \  \alpha \ \   Z_{\frac{\alpha }{2} }

Hence for  reducing confidence level the margin of error will be reducing

  The  confidence interval is mathematically represented as

        \= x  - E  <  \mu <  \= x  + E

Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value  reduces, the margin of error  reduces and the confidence interval becomes narrower

3 0
3 years ago
Pls help me !! will mark brainliest... i just need you to solve for m&lt;1 and m&lt;7 !! thanks !!
frez [133]

Step-by-step explanation:

=( n-2)180

= ( 4 - 2 )180

= 360

So, 144 + 90 + m<2 +m<1 = 360

144 + 90 + 85 + m<1 = 360

319 + m<1 = 360

m<1 = 360 - 319

m<1 = 41

their is an unknown angle so let's call it x

let's find x first ( m<6=49)

x + m<6 = 180

x + 49 = 180

x = 180 - 49

x = 131

Now let's find m<7

m<7 + 38 + m<4 + x = 360

m<7 + 38 + 85 + 131 = 360

m<7 + 254 = 360

m<7 = 360 - 254

m< 7 = 106

8 0
3 years ago
G=4ca-3ba, find a <br>Also plz show how u found the answer.
lina2011 [118]
G=4ca-3ba <=> G=a(4c-3b)

                   <=> a=G/(4c-3b)
8 0
3 years ago
Read 2 more answers
I need help due today at 6
Fofino [41]

Answer:


Step-by-step explanation:


3 0
3 years ago
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