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8090 [49]
1 year ago
13

What are the first five terms in the recursive sequence defined by the following?

Mathematics
1 answer:
kolezko [41]1 year ago
5 0

The first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

<h3>Recursive function</h3>

Given the nth term of a recursive expression shown below

an =an-1 - 1.4

where

an-1 is the preceding term

a1 is the first term

an is the nth term

an-1 is

Given the following

a1 = 0

For the second term a2

a2 = 0 - 1.4

a2 = -1.4

For the third term a3

a3 = -1.4 - 1.4

a3 = -2.8

For the fourth term a4

a4 = -2.8 - 1.4

a4 = -4.2

For the fifth term a2

a5 = -4.2 - 1.4

a5 = -5.6

Hence the first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

Learn more on recursive function here: brainly.com/question/489759

#SPJ1

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fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
How many times longer is 3 1/2 to 2 1/2
Alik [6]

Answer:

1.4 times as long

Step-by-step explanation:

3 1/2 (convert to mixed number) --> 7/2

2 1/2 (convert to mixed number) --> 5/2

(7/2) / (5/2) --> 7/5 --> 1.4

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2 years ago
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Step-by-step explanation:

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To solve for x, rewrite the equation using properties of logarithms.

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The result can be shown in multiple forms.

Exact Form:

x= e^4/3+7

Decimal Form:

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