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8090 [49]
2 years ago
13

What are the first five terms in the recursive sequence defined by the following?

Mathematics
1 answer:
kolezko [41]2 years ago
5 0

The first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

<h3>Recursive function</h3>

Given the nth term of a recursive expression shown below

an =an-1 - 1.4

where

an-1 is the preceding term

a1 is the first term

an is the nth term

an-1 is

Given the following

a1 = 0

For the second term a2

a2 = 0 - 1.4

a2 = -1.4

For the third term a3

a3 = -1.4 - 1.4

a3 = -2.8

For the fourth term a4

a4 = -2.8 - 1.4

a4 = -4.2

For the fifth term a2

a5 = -4.2 - 1.4

a5 = -5.6

Hence the first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

Learn more on recursive function here: brainly.com/question/489759

#SPJ1

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sergey [27]

Answer:

P(B|A)=0.25  , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

P(B)= 0.4

P(A∩B) = 0.2

Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

P(B|A) = P(A∩B)/P(A)

      = (0.2) / (0.8)  

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

          = (0.2)/(0.4)

P(A|B) =0.5

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3 years ago
Determine whether the following series converge or diverge
Mars2501 [29]
An alternating series \sum\limits_n(-1)^na_n converges if |(-1)^na_n|=|a_n| is monotonic and a_n\to0 as n\to\infty. Here a_n=\dfrac1{\ln(n+1)}.

Let f(x)=\ln(x+1). Then f'(x)=\dfrac1{x+1}, which is positive for all x>-1, so \ln(x+1) is monotonically increasing for x>-1. This would mean \dfrac1{\ln(x+1)} must be a monotonically decreasing sequence over the same interval, and so must a_n.

Because a_n is monotonically increasing, but will still always be positive, it follows that a_n\to0 as n\to\infty.

So, \sum\limits_n(-1)^na_n converges.
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Answer:

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Step-by-step explanation:

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1.2x-2.4+1.2x-2

2.4x-4.4

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