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2 years ago

Two trains, A and B are moving at a speed of 20 km per hour

Chemistry

2 answers:

Fittoniya [83]2 years ago

6 0

Answer:

$\fbox {kinetic motion}$

Explanation:

As the trains are clearly in motion, we can understand the these trains possess kinetic energy, which is by virtue of a motion of a body.

Bad White [126]2 years ago

6 0

Answer:

type of energy that two train have are kinetic energy

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When a solid is placed in a container and heat is applied, a phase change occurs. Watch the video and identify which of the foll

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Answer:

Explanation:"Watch the video and identify which of the following statements are correct." Excuse no video

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3 years ago

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A wooden artifact from an ancient tomb contains 60% of the carbon-14 that is present in living trees. How long ago was the artif

noname [10]

Answer:

The age of the sample is 4224 years.

Explanation:

Let the age of the sample be t years old.

Initial mass percentage of carbon-14 in an artifact = 100%

Initial mass of carbon-14 in an artifact = $[A_o]$

Final mass percentage of carbon-14 in an artifact t years = 60%

Final mass of carbon-14 in an artifact = $[A]=0.06[A_o]$

Half life of the carbon-14 = $t_{1/2}=5730 years$

$k=\frac{0.693}{t_{1/2}}$

$[A]=[A_o]\times e^{-kt}$

$[A]=[A_o]\times e^{-\frac{0.693}{t_{1/2}}\times t}$

$0.60[A_o]=[A_o]\times e^{-\frac{0.693}{5730 year}\times t}$

Solving for t:

t = 4223.71 years ≈ 4224 years

The age of the sample is 4224 years.

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3 years ago

When the reaction shown is correctly balanced, the coefficients are HNO3 + KOH → KNO3 + H2O

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Coefficients are 1,1,1,1

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3 years ago

How are mutation affects different?

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Mutation affects can be different just with changes as small as the substitution of a single DNA building block or nucleotide base with another nucleotide base

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2 years ago

If the observed value for a density is 0.80 g/mL and the accepted value is 0.70 g/mL what is the percent error?

kvv77 [185]

Answer:

<h2>The answer is 14.29 %</h2>

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual density = 0.70 g/mL

error = 0.8 - 0.7 = 0.1

So we have

$P(\%) = \frac{0.1}{0.7} \times 100 \\ = 14.285714...$

We have the final answer as

Hope this helps you

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3 years ago