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Mademuasel [1]
3 years ago
6

Name the salt k4[pt(co3)2f2] given that the carbonate ion acts as a monodentate ligand in the complex. the oxidation number of p

latinum is +2. enter the name.
Chemistry
2 answers:
jenyasd209 [6]3 years ago
8 0

Answer:

Potassium dicarbonatedifluoroplatinate (II)

Explanation:

Hello,

Based on the IUPAC rules, the given compound is a complex called potassium dicarbonatodifluoroplatinate (II) as long as the carbonate ion is present twice as a monodentate ligand therefore it is preceded by a "di" prefix. In addition, two fluorines are also present with the "di" prefix as well as a platinum which complete the anionic section including +2 as the platinum oxidation state.

Best regards.

MA_775_DIABLO [31]3 years ago
4 0
The IUPAC name of compound is Potassium dicarbonatodifluoroplatinate (II)

*Note, since carbonate ion is acting as monodentate ligand, prefix of 'di' is used. In case, if it had been a bidentate ligand prefix 'bis' would have been used.
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At a given temperature, the elementary reaction A --->B in the forward direction is first order in A with a rate constant of
Pani-rosa [81]

Answer:

The value of the equilibrium constant for the reaction A ⇒ B is Kc = 1.72 × 10³.

The value of the equilibrium constant for the reaction B ⇒ A is K'c = 5.81 × 10⁻⁴.

Explanation:

For the reaction A ⇒ B, the equilibrium constant (Kc) is equal to the forward rate constant (kf) divided by the reverse rate constant (ki).

Kc=\frac{kf}{ki} =\frac{1.60 \times 10^{2} s^{-1}   }{ 9.30 \times 10^{-2} s^{-1}} =1.72 \times 10^{3}

If we consider the inverse reaction B ⇒ A, its equilibrium constant (K'c) is the inverse of the forward reaction equilibrium constant.

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