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Nana76 [90]
3 years ago
6

What is the name of the functional group that is attached to this hydrocarbon? The first and last of a chain of three carbons ar

e each single bonded to 3 H; the center carbon is double bonded to O. alkyl halide alcohol carbonyl ketone
Chemistry
1 answer:
disa [49]3 years ago
4 0

Answer:

Ketone

Explanation:

As you are stating here, we have a carbonated chain of three carbons, and the first and last has 3 Hydrogens, then this means that we have CH₃ . The center carbon is a carbon double bonded to oxygen.

In general terms this belongs to the carbonyl group. However, this alone does not represent a functional group, but when it's in a chain with other radycals or chains, it becomes a functional group.

In this case, the molecule you are talking here is the following:

CH₃ - CO - CH₃

This molecule is known as the Acetone, and has the general form of:

R - CO - R'

Which belongs to a ketone as a functional group.

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\Delta H_{I_2(g)}=62.438\ KJ/mol\\\\\Delta H_{Cl_2(g)}= 0.0\ KJ/mol\\\\\Delta H_{ICl(g)}=17.78\ KJ/mol

For given reaction, I_2(g)+Cl_2(g)\ -->\ 2ICl(g)

\Delta H_{rxn}=2\Delta H_{ICl(g)}-\Delta H_{I_2(g)}-\Delta H_{Cl_2(g)}\\\\\Delta H_{rxn}=2(17.78)-0-62.438\ KJ/mol\\\\\Delta H_{rxn}=-26.878\ KJ/mol

For , 2.41 moles of I_2 :

\Delta H_{rxn}=2.41\times (-26.878)\ KJ\\\\\Delta H_{rxn}=-64.78\ KJ

We know :

\Delta S = -\dfrac{\Delta H_{rxn}}{T}\\\\\Delta S = -\dfrac{-64.78}{298}\ KJ/K\\\\\Delta S =-0.21738 \ KJ/K\\\\\Delta S=-217.38\ J/K

Hence, this is the required solution.

7 0
4 years ago
Currently this lab is run qualitatively asking only for whether a solution is acidic, neutral, or basic. If quantitative informa
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Answer:

The only PH range which is not covered by any of the given components of the universal indicator is 7.6-8.0

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Write the balance chemical equation for propane.
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A metal crystallizes in the face‑centered cubic (FCC) lattice. The density of the metal is 12020 kg/m3, and the length of a unit
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Answer:

  1.7700×10^-22 g

Explanation:

A face-centered-cubic cell contains 4 atoms, so the volume per atom is ...

  (389.80×10^-12 m)³/(4 atoms) ≈ 1.4725×10^-29 m³

Then the mass of 1 atom is ...

  (12020 kg/m³)(1.4725×10^-29 m³) ≈ 1.76995×10^-25 kg

  ≈ 1.7700×10^-22 g

_____

<em>Additional comment</em>

That is the approximate mass of a Palladium atom.

7 0
3 years ago
Read 2 more answers
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