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OLEGan [10]
2 years ago
11

Determine the fall (drop) on 20' of drainage piping with a 1/4" per ft. grade

Mathematics
1 answer:
navik [9.2K]2 years ago
7 0

The Fall (drop)  of drainage piping is: A. 5".

<h3 /><h3>Fall (drop) of drainage piping </h3>

In order to determine the fall (drop) of drainage piping we would need to multiply the drainage piping by the inch per feet.

Hence:

Using this formula

Fall (drop) of drainage piping = Drainage piping× inch per feet

Where:

Drainage piping=20

Inch per feet=1/4"

Let plug in the formula

Fall (drop) of drainage piping =20×1/4"

Fall (drop) of drainage piping =5"

Therefore the correct option is A. 5".

Learn more about Fall (drop)  of drainage piping here:brainly.com/question/1084949

#SPJ1

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tekilochka [14]

Answer:

m=4

Step-by-step explanation:

to find the slope m take two points : (17,68). (20,80)

m=y2-y1/x2-x1

m=80-68/20-17=12/3= 4

m=4

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4 years ago
A parent function f(x)=4x-5 is transformed to f(x)+3. which statement about the graph of f(x)+3 is true?
Andreas93 [3]

Answer:

B

Step-by-step explanation:

f(x) is just another way of saying y, so this function is really y=4x-5. So if you do y+3 then the y intercept will increase by 3 shifting the graph up 3 units.

8 0
3 years ago
For what values of m does the graph of y = 3x^2 + 7x + m have two x-intercepts? a) m&gt;12/49 b) m&lt;12/49 c) m&lt;49/12 d) m&g
den301095 [7]

The quadratic formula, has a part we call the "discriminant" defined by the variables that are inside the square root, and is denotated by "delta":

<span>Δ=<span>b2</span>−4ac</span> Whenever we solve a quadratic equation that is complete and we analyze the discriminant, we can get 3 scenarios: <span>if→Δ>0<span>=></span>∃<span>x1</span>,<span>x2</span>/a<span>x2</span>+bx+c=0</span> This just means: "if the discriminant is greater than zero, there will exist two x-intercepts" And for the second scenario: <span>if→Δ=0→∃<span>xo</span>/a<span>x2</span>+bx+c=0</span> This means: "if the discriminant is equal to zero, there will be one and only one x-intercept" And for the last scenario: <span>if→Δ<0→∃x∉R/a<span>x2</span>+bx+c=0</span> This means that :"if the discriminant is less than zero, there will be no x-intercepts" So, if we take your excercise and analyze the the discriminant: <span>3<span>x2</span>+7x+m=y</span> we will find the values that satisfy y=0 : <span>3<span>x2</span>+7x+m=0</span> And we'll analyze the discriminant: <span>Δ=<span>72</span>−4(3)(m)</span> And we are only interested in the values that make the discriminant equal zero: <span><span>72</span>−4(3)(m)=0</span> All you have to do is solve for "m".

6 0
3 years ago
Which linear function represents a slope of ? A two column table with five rows. The first column, x, has the entries, 3, 6, 9,
Temka [501]

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

8 0
1 year ago
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