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2 years ago

ASAP NOW below is the question

Mathematics

1 answer:

eimsori [14]2 years ago

5 0

The mean of the data set A is 4.58 while the mean of data set B is 5.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

The mean of a set of numbers is the average of that group of number. It is the ratio of the sum of the data to the total number of data.

Mean of data set A = [(3 * 1) + (4 * 3) + (5 * 2) + (6 * 2) + (7 * 3) + (8 * 1)] / (1 + 3 + 2 + 2 + 3 + 1) = 4.58

Mean of data set B = [(4 * 2) + (5 * 2) + (6 * 2)] / ( 2 + 2 + 2) = 5

The mean of the data set A is 4.58 while the mean of data set B is 5.

Find out more on equation at: brainly.com/question/2972832

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The graph represents a functional relationship. On a coordinate plane, a straight line with a negative slope begins at point (1,

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3 years ago

What is the number? I did many ways but i didn't found it, please guys help me with it.

Advocard [28]

Answer:

A). 15

B). -1.2

Step-by-step explanation:

A). [10(x+3)]-20 = 160

10x+30-20 = 160

10x+10 = 160

10x = 160-10

10x = 150

x = 150/10

x = 15

B). 5{[4(8+(5x))]-9} = 85

5(32+20x+9) = 85

5(32+9+20x) = 85

5(41+20x) = 85

205+100x = 85

100x = 85-205

100x = -120

100x/100 = -120/100

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HOPE THIS HELPS!!!

3 0

3 years ago

A spring has natural length 20 cm. Compare the work W1 done in stretching the spring from 20 cm to 30 cm with the work W2 done i

sashaice [31]

Answer:

W1 = W2 = 50k Joules (assuming W1 and W2 have the same force constant, k)

W1 - W2 = 0

Step-by-step explanation:

Work done in stretching a spring is given by 1/2ke^2

Where, k is force constant and e is extension

e1 = 30cm - 20cm = 10cm

W1 = 1/2k(e1)^2 = 1/2×k×10^2 = 50k Joules

e2 = 40cm - 30cm = 10cm

W2 = 1/2k(e2)^2 = 1/2×k×10^2 = 50k Joules

W1 = W2 = 50k Joules provided W1 and W2 have equal force constant

Therefore, W1 - W2 = 0

7 0

3 years ago

a cup is 6.4 cm tall, not including the 0.6 cm lip. cups are stacked inside one another. select the function that represents the

Alja [10]

Answer: 20

H(c) = 6.4 + 0.6c

6.4 is the constant.

When the height of the cups is 18.4 the function is:

18.4 = 6.4 + 0.6c

Then, you add 6.4 from both sides

18.4 - 6.4 + 6.4 = 6.4 + 0.6c - 6.4 + 6.4

Simplify

18.4 = 6.4 + 0.6c

Switch sides

6.4 + 0.6c = 18.4

Multiply both sides by 10

6.4 x 10 + 0.6c x 10 = 18.4 x 10

Refine

64 + 6c = 184

Subtract 64 from both sides

64 + 6c - 64 = 184 - 64

Simplify

6c = 120

Divide both sides by 6

6c/6 = 120/6

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8 0

3 years ago