Answer:
The correct option is;
b. Stem and leaf plot
Step-by-step explanation:
A stem-and-leaf plot shows the data shape and the densities of the different classes in a graphical form such that the information in the data such as the data characteristics are self displayed by the data numbers arranged in the stem-and-leaf plot. The stem-and-leaf plot keeps the raw numerical data, in the form they were obtained and by their arrangement, outliers are easily spotted.
The ordered pair that is the best estimate for the solution of the system of equations is (7, 1/2)
The given system of equations is:

Equate equations (1) and (2)

Solve for x in the equation above

Substitute x = 7 into equation (1)

The ordered pair that is the best estimate for the solution of the system of equations is (7, 1/2)
Learn more on system of equations here: brainly.com/question/13729904
Answer:
a)
b) ![P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668](https://tex.z-dn.net/?f=P%28X%3E%202%29%3D1-P%28X%5Cleq%202%29%3D1-%5B0.0211%2B0.0995%2B0.211%5D%3D0.668)
c)
Step-by-step explanation:
1) Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
2) Solution to the problem
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
Where (nCx) means combinatory and it's given by this formula:
Part a
Part b
![P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]](https://tex.z-dn.net/?f=P%28X%3E%202%29%3D1-P%28X%5Cleq%202%29%3D1-%5BP%28X%3D0%29%2BP%28X%3D1%29%2BP%28X%3D2%29%5D)
![P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668](https://tex.z-dn.net/?f=P%28X%3E%202%29%3D1-P%28X%5Cleq%202%29%3D1-%5B0.0211%2B0.0995%2B0.211%5D%3D0.668)
Part c