<img src="https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%200%20%28%5Cfrac%7Bx%28x-2%29%7D%7B2-2e%5E2x%7D%20%29" id="TexFormula1" ti

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1 year ago

tle="\lim_{x \to 0 (\frac{x(x-2)}{2-2e^2x} )" alt="\lim_{x \to 0 (\frac{x(x-2)}{2-2e^2x} )" align="absmiddle" class="latex-formula">
Help evaluting this limit

Mathematics

1 answer:

krek1111 [17]1 year ago

7 0

Answer: 0

Step-by-step explanation:

Substituting in x=0, we get

$\frac{0(0-2)}{2-2e^{2}(0)}=0$

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===============================================

Work Shown:

Let $y = \sqrt[5]{x^3}$

So the equation reduces to -7 = 8-3y

Let's solve for y

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y = 5

-----------

Since $y = \sqrt[5]{x^3}$ and y = 5, this means we can equate the two expressions and solve for x

$y = 5$

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$x = \sqrt[3]{125}*\sqrt[3]{25}$

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