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inna [77]
2 years ago
6

tle="\lim_{x \to 0 (\frac{x(x-2)}{2-2e^2x} )" alt="\lim_{x \to 0 (\frac{x(x-2)}{2-2e^2x} )" align="absmiddle" class="latex-formula">
Help evaluting this limit
Mathematics
1 answer:
krek1111 [17]2 years ago
7 0

Answer: 0

Step-by-step explanation:

Substituting in x=0, we get

\frac{0(0-2)}{2-2e^{2}(0)}=0

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3 0
2 years ago
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lara31 [8.8K]

Answer:8600

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8 0
3 years ago
How can I solve 900-382?
BlackZzzverrR [31]

   899

   900

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<h3>   517</h3><h3>Hope this helps</h3>
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3 years ago
Need answer asap!!!!!<br><br> how would i solve this?
lesya [120]

The height of the building to the nearest tenth of a meter is; 13 m

<h3>How to make use of Cosine Rule?</h3>

The slant line from the top of Trevor's head to the base of the building is gotten from Pythagoras theorem;

15/x = sin 36°

x = 15/sin 36

x = 25.52 m

Angle between that slant line and base of building is;

90 - tan⁻¹(1.5/14) = θ

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h = 13 m

Read more about Cosine Rule at; brainly.com/question/4372174

#SPJ1

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1 year ago
Which is one way to check 102 ÷ 6 = 17
Nikolay [14]
The answer is B. 100/5=20 hope i helped

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