[4 over x equals 5 over 10]
Solve for x, so you need to isolate/get x by itself in the equation.
Multiply x on both sides
Multiply the inverse of 5/10, which is 10/5, to get rid of the fraction and get x by itself
8 = x
Answer:
15.8 (15/8)
Step-by-step explanation:
First, we turn the mixed numbers into fractions by multiplying the whole number by the denominator and this answer into the numerator:
2 1/2=5/2
1 1/3=4/3
now to divide, we keep the first fraction, change the divide to a multiply, and then flip the second fraction:
5/2·3/4
Now, simply multiply:
5/2·3/4=15/8 (15.8 if you need a decimal)
And you have your answer! hope this helped!
This is the concept of algebra: The answers to the questions will be as follows:
1. What is AD/AM in the simplest form:
AD/AB is the ratio of AD to AB. This will calculated as follows:
AD=9 units
AB=3 units
thus:
9/3=3
Hence, we conclude that the answer is D. 3
2] What is slope of BE/ slope of AE in simplest form:
slope=(Δy-axis)/(Δx-axis)
slope of AE
=(5-0)/(4-0)
=5/4
slope BE
slope=(5-0)/(4-3)=5/1=5
therefore the ratio of the two slope will be:
BE/AE
=5/(5/4)
=4
The answer is A.4
3. What is the value of x in the proportion (x-1)/5=(4x+2)/35?
To get the value of x we solve the above proportion:
(x-1)/5=(4x+2)/35
35(x-1)=5(4x+2)
35x-35=20x+10
putting like terms together we get:
35x-20x=10+35
15x=45
dividing both sides by 15
x=45/15
x=3
Hence the answer is B.3
4. What is the value of x in the proportion:
(x+1)/(x+3)=15/21
to get the value of x we solve the above:
first we begin by cross multiplying the proportion, this will give us:
21(x+1)=15(x+3)
21x+21=15x+45
putting like terms together we get:
21x-15x=45-21
6x=24
dividing both sides by 6 we get
x=4
∴ x=4
5. The lengths of the sides of a triangle are in extended ratio 3:10:12. The perimeter is 400 cm. What is the length of the longest side in cm.
solution:
Here we introduce the variable x such that the perimeter is:
3x+10x+12x=400
25x=400
x=400/25
x=16
The longest side will be:
12×16=192 cm
(2, 6) because it is halfway between both endpoints
