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OverLord2011 [107]
2 years ago
9

Helppppppppppppppppp​

Mathematics
2 answers:
Dahasolnce [82]2 years ago
5 0

Answer:

9: Division

10: 3 / 4

11; 4 / 5

12: 0.36

13: 24 / 50

14: 11 / 100

15: 5.01

Step-by-step explanation:

note that my number 9 answer is not the same as the other person's own

and that the answer to number 14 is not in the options

lions [1.4K]2 years ago
3 0

Answer:

<h2>9) Multiplication</h2><h2>10) </h2><h2>\frac{3}{4}</h2><h2>11) </h2>

\frac{4}{5}

<h2>12) 0.36</h2>

<h2>13) </h2>

\frac{12}{25}

<h2>14)</h2>

\frac{1}{9}

<h2>15) 5.9</h2>

Step-by-step explanation:

<h2>This might be helpful and believe me dude, these questions are the most important questions for your exams.</h2><h2 /><h2>Keep Studying ☺️❤️</h2>
You might be interested in
How many positive integers are in the solution set of the inequality below? -2x + 1 ≥ -6
coldgirl [10]

Answer:

3 integers, with values: 1,2,3

Step-by-step explanation:

-2x+1>=-6

2x-1<=6

2x<=7

Positive integers: x=1,2,3

Count: 3

7 0
2 years ago
Read 2 more answers
the height of an equivalent triangle is 15cm and it's perimeter is 36cm find the area of the triangle​
OlgaM077 [116]

Answer:

The area is 72 cm².

Step-by-step explanation:

Since it is equivalent triangle

h = b

so,

b + b + b (since all sides are equal)= 36 cm

3b = 36 cm

or, b = 36/3

so, b = 12 cm

so

area of triangle = (1/2)×b×h

= (1/2)×12cm×12cm

= 6cm × 12cm

= 72 cm²

4 0
2 years ago
Whats the congruence of these two triangles ? none ? sas ? asa ? or sss ?
Ket [755]

Answer:

choice #3) similar by SSS

The corresponding sides do have the correct ratios.

3 0
2 years ago
Read 2 more answers
Write a real world problem for 5n+8=43
lianna [129]

5n=43-8

5n=35

n=7

This is 7

8 0
3 years ago
Tough one!
frosja888 [35]
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get

= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],

applying L'Hospital rule again ,we get,

 = > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2

For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.

Hence 2a - b =0 => 2a = b ------(A)

limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,

= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2

[0/0 form], applying L'Hospital rule again ,we get,

limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2

from (A), we have , 2a = b => 2a = -2 => a = -1

Hence a =-1 & b = -2
7 0
2 years ago
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