The solution for this problem would be:
Given that there is 99.999%.
Let denote n as the network servers and p as the reliability of each server.
So the probability that the network uptime = 1 - (1 - p)^n
Therefore, (1-p) ^n = 0.00001
a. x= log(1-.99999)÷log(1-.97)= 3.2833 is the answer
1-(1-.97)^3= 0.99999 + 0.0001 = 1
b. x = log(1-.99999)÷log(1-.88) = 5.43 is the answer
1-(1-.88)^3= 0.99 + 0.0001 = approx 1
For the answer to the question above, For θ the range is between -infinity and infinity,
<span>While y falls in the range from -1 to 1.
because </span><span>y is an element of [-1, 1]</span>
I hope my answer helped you in your problem. Have a nice day!
(3x^3+2x^2-5x) -(8x^3-2x^2)
-5x^3 -5x is the answer, there's not really any work to show, just subtract.
