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gizmo_the_mogwai [7]
1 year ago
15

Find the area of the region enclosed by the curves yequals

Mathematics
1 answer:
Step2247 [10]1 year ago
6 0

The area enclosed by the given 2 curves is; 8/3 or 2.67

<h3>How to Solve Integration with Limits?</h3>

We want to find the area enclosed by the curves;

y = x² - 2x

y = -x² + 2x

The point of intersection of the parabola and the line is given by;

x² - 2x = -x² + 2x

2x² - 4x = 0

Solving this gives;

x = 0, 2

Therefore, the area bounded by the parabola and the line between x = 0 and x = 2 is given as;

A = ∫₀² (-x² + 2x - x² + 2x)

A = ∫₀² (-2x² + 4x)

Using online integration calculator here gives;

A = 2.67

Read more about Integration at; brainly.com/question/14388434

#SPJ1

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Calculators were purchased at $62 per dozen and sold for $38 for three calculators. Find the profit for selling 5 dozen calculat
dedylja [7]
Each calculator sold for $12.67 . So 5 would be $63.35
8 0
2 years ago
Read 2 more answers
1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
Which diagram shows that the two triangles must be congruent
Arte-miy333 [17]

Answer:

D. 2 and 3 only

Step-by-step explanation:

I took the test. I am in Honors Geometry.

5 0
3 years ago
Connected to the question before this
lesya [120]

Answer:

(4)Angle A is 63°

Step-by-step explanation:

To find angle A here is what you have to do

(1) triangle A is an Isosceles triangle which has two of its angles being equal.

(2) To find A we hv to look for the interior angles of the triangle. If u look carefully there is this angle outside the triangle .we can use a property called "Angles on a straight line

(3) " Angles on a straight line sum up to 180°" When u do that ur equation will look like this

126+(x)=180°. u may be wondering hw did we get the x?? well i named the angle we dont know with any valuable like T,F etc .when u group like terms ur equation should look like this (x)=180°-126°

if u subtract ur answer should be x=63°

(B) if u look closely u will see there are two triangles. The one to the far right is an Isosceles triangle why because there is this double stroke indicating it is an Isosceles triangle. Remember an Isosceles triangle has its bases being equal. so the the triangle has two angles of 30°. so If we want to find B we first have to find the interior angles of the Isosceles triangle . so our epuarion will be like this 30°+30°+(X)=180°

U group like terms so it will look like this x=180°-60° so,

x= 120°

So now T=120°

Now to find B

we write the equation like this T+(W)=180°

we put the value of T into the Equation w=180°-120 the answer is 60°

So to find B we find the interior angles of the triangle and the interior angles of the Isosceles triangle sum up to 180. so it will look like this B+90+60=180

Nb they should be in Degrees

finally u group like terms. ur equation should look like this B=180-150

ur answer should be B=30°

7 0
3 years ago
I’m not sure what the answer can I get some help
Ronch [10]

Answer:

B.) 9.25p + 8.9t\leq 100

Step-by-step explanation:

8 0
2 years ago
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