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fiasKO [112]
4 years ago
12

I need help with intercepts from a graph

Mathematics
1 answer:
Rina8888 [55]4 years ago
8 0

Explanation: The y axis is the line that goes up and down, vertical. The x axis is the line that goes straight across, horizontal. So, when looking for intercepts we have to see what numbers your graphed line goes through.

Make sure when you are writing your points you write it in (x,y) form. If you don't it will be wrong.

So, for our x intercept it would be -7,0.

This is because your graphed line goes through x at -7 and it has no y, so that would be 0.

For your y intercept, it would be 0,2

This is because our line does not go through x, so we make that 0. It does go through y at 2.

Hope this helps :)

If you need elaboration on anything let me know. I know sometimes with math it is kind of hard to explain through typing.

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Determine the next three terms of 180,360,540,720​
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Answer:

900, 1080, 1260

Step-by-step explanation:

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8 0
2 years ago
The difference of two numbers is 30. their quotient is 6. what are the two numbers
BlackZzzverrR [31]
Well, the quotient must be bigger/smaller

lets say the numbers are x and y
x>y

so
x-y=30 and x/y=6
multiply both sides by y in 2nd equation
x=6y
subsitute 6y for x in other equation

6y-y=30
5y=30
divide by 5
y=6

sub back
x=6y
x=6(6)
x=36


the numbers are 36 and 6

but they could also be -36 and -6 because -36/-6=6 and -6-(-36)=30


the 2 numbers are 36 and 6 or -36 and -6
8 0
4 years ago
The variable, y, varies directly with x. if y = 20 when x = 25, what is y when x = 43? Also please explain so I can understand t
Gwar [14]

Answer:

25

Step-by-step explanation:

4 0
2 years ago
Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2
ankoles [38]

Option C:

2 g^{3}-5 g^{2}+6

Solution:

Given expression:

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

To find which expression is equal to the given expression.

$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}

Expand the term -\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12

         $=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}

Arrange the like terms together.

         $=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}

         $=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}

Factor the numerator 2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)

         $=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}

Cancel the common factor g + 2, we get

         =2 g^{3}-5 g^{2}+6

Hence option C is the correct answer.

8 0
3 years ago
Read 2 more answers
Write a common denominator for 1 fourth and 5 sixth
soldi70 [24.7K]
The common denominator is 12, the lowest number that has both six and four as factors.
6 0
3 years ago
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