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melomori [17]
2 years ago
5

The function f(x) = 300(0.5)x/100 models the amount in pounds of a particular radioactive material stored in a concrete vault, w

here x is the number of years since the material was put into the vault. Find the amount of radioactive material in the vault after Round to the nearest whole number.
Mathematics
1 answer:
allsm [11]2 years ago
5 0

The amount of the radioactive material in the vault after 140 years is 210 pounds

<h3>How to determine the amount</h3>

We have that the function is given as a model;

f(x) = 300(0.5)x/100

Where

  • x = number of years of the vault = 140 years
  • f(x) is the amount  in pounds

Let's substitute the value of 'x' in the model

f(x) = 300(0.5)x/100

f(x) = \frac{300(0.5) * 140}{100}

f(x) =\frac{21000}{100}

f(140) = 210 pounds

This mean that the function of 149 years would give an amount of 210 pounds rounded up to the nearest whole number.

Thus, the amount of the radioactive material in the vault after 140 years is 210 pounds

Learn more amount radioactive decay here:

brainly.com/question/11117468

#SPJ1

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Pepsi [2]

We need to find the base x in the following equation:

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Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

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now add (219 + 190 + 81) = 490/30

now divide 490 ÷ 30 = 16 1/3

Your answer is 16 1/3

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