So lonely have no friend

Mathematics

1 answer:

Assoli18 [71]3 years ago

7 0

Answer:

NOICE

Step-by-step explanation:

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for an art project you make a square print with a side length of 8 inches. You make a frame using strip of wood 1 1/4 inch wide.

lord [1]

Given that square print has side length = 8 inches

Given that you make a frame using strip of wood 1 1/4 inch wide. Since frame is on both sides of the square print so new side length after adding the frame = $1 \frac{1}{4} + 8 + 1 \frac{1}{4} = 10 + \frac{2}{4} = 10 + \frac{1}{2} = 10.5$ inches

Area of the square is given by formula $= x^2$ where x is the side of square

Shape of the frame including print will also be square so

Area of the frame including print $= 10.5^2 = 110.25$ square inches

Area of the print = $8^2 = 64$ square inches

We have to find the area of frame only so we can subtract area of print from the total area

Area of frame = [Area of frame including print] - [Area of print]

Area of frame = 110.25-64 = 46.25

Hence final answer is 46.25 square inches

7 0

3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

iris [78.8K]

Answer:

t = 15.42 s

Step-by-step explanation:

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation.

$y=-16x^2+242x+73$

We ned to find the time when the rocket will the ground. For this, y = 0

$-16x^2+242x+73=0$

It is a quadratic equation whose solution is given by :

$x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 242 and c = 73

$x=\dfrac{-b+ \sqrt{b^2-4ac} }{2a}, x=\dfrac{-b-\sqrt{b^2-4ac} }{2a}\\\\x=\dfrac{-242+ \sqrt{(242)^2-4(-16)(73)} }{2(-16)}, x=\dfrac{-242- \sqrt{(242)^2-4(-16)(73)} }{2(-16)}\\\\=-0.295\ s, 15.42\ s$