Solve the equation. -9×+1==×+17 O x=-8 O x = -2 O x=2 © ) x=8

In a test of a gender-selection technique, results consisted of 248 baby girls and 13 baby boys. based on this result, what is

Rashid [163]

When it comes to probability, the answer is always expressed as part of a whole. With that being said, your answer for this problem can be a ratio, fraction or in percentage. Probability is the study of finding the chances or odds of an event happening with the use of statistics. You are already given the statistics of baby girls and baby boys. Note that you are asked to find the probability of the baby being a girl. So, the part here includes the 248, while the whole is 248+13 = 261. Therefore, the probability is 248/261 or 0.95 or 95%. That means that the likelihood of having a girl baby using this technique is very high.

6 0

3 years ago

The process of eliminating jobs to help cut expenses is known as

Angelina_Jolie [31]

Answer:

known as mass layoffs and u lose your job security

Step-by-step explanation:

8 0

3 years ago

If p(x) = 2x2 – 4x and q(x) = x – 3, what is (pxq) (x)

balu736 [363]

(4-4x)(x-3)
4x-12-(4x^2)+12x
(-4x^2)+16x-12=(pxq)(x)

5 0

3 years ago

The measure of ∠1 is 65°. What is the relationship between ∠1 and ∠2

bagirrra123 [75]

Answer:

if its complemantary it is 24 degrees

if it supplemntary it is 115 degrees

Step-by-step explanation:

7 0

3 years ago

According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

Let $\hat p$ = sample proportion of Americans who can order a meal in a foreign language

The z-score probability distribution for sample proportion is given by;

Z = $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( $\hat p$ > 0.50)

P( $\hat p$ > 0.06) = P( $\frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ > $\frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } }$ ) = P(Z > 0.85) = 1 - P(Z $\leq$ 0.85)

= 1 - 0.80234 = 0.19766

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0

4 years ago