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gregori [183]
3 years ago
11

0.5 is 10 times as great as

Mathematics
2 answers:
GenaCL600 [577]3 years ago
7 0
The answer is:  " 0.05 " .
____________________________
Explanation:
____________________________
Take  "0.5" and divide by "10" :

0.5 /10 = 0.05 .
____________________________
Bingel [31]3 years ago
3 0
.5
because when you do .05 x 10 you get .50
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Bailey studies 3 days for her final exam in history. The first day she studied 1 1/2 hours on day 2 she studied 1/2 as long as s
borishaifa [10]
1st day: 1 1/2 hours
2nd day: half of first day = 1/2 * 1 1/2 hours
3rd day: 2 1/2 times as long as first day: 2 1/2 * 1 1/2 hours

1 1/2 + 1/2 * 1 1/2 + 2 1/2 * 1 1/2 =

= 3/2 + 1/2 * 3/2 + 5/2 * 3/2

= 3/2 + 3/4 + 15/4

= 6/4 + 3/4 + 15/4

= 24/4

= 6

Answer: She studied for 6 hours over the 3-day period.
5 0
4 years ago
Read 2 more answers
Angle RST is a right angle. Angle RSU has a measure of 25°.
IrinaK [193]
Since angle RST is a right angle, it has a measure of 90°. 
Angle RSU could either be inside or outside the right angle. 
If Angle RSU is inside, the measurement of Angle TSU is:
90°- 25° = 65°

If Angle RSU is outside, the measurement of Angle TSU is:
90° + 25° = 115°
7 0
3 years ago
Read 2 more answers
85cm + 258cm + 13cm all over <br> 2
kow [346]

178

You add 85cm plus 258cm plus 13cm then you get the answer divide it by 2 you get

178cm

6 0
3 years ago
According to the graph above, College R showed
marusya05 [52]

Given:

The graph that shows the ennoblement for college R between 1950 and 2000.

To find:

The two decades that has the greatest change in enrollment.

Solution:

From the given graph, it is clear that the change in the enrollment is:

From 1950 to 1960 is 4-3.5=0.5 thousand.

From 1960 to 1970 is 5-4.5=1.5 thousand.

From 1970 to 1980 is 5.5-5=0.5 thousand.

From 1980 to 1990 is 6.5-5.5=1 thousand.

From 1990 to 2000 is 7-6.5=0.5 thousand.

The two decades 1960-1970 and 1980-1990 have the greatest change in enrollment.

5 0
3 years ago
Hey can you please help me posted picture of question :)
harina [27]
Y=(x-3)^2+36
Using (a-b)^2=a^2-2ab+b^2, with a=x and b=3
y=(x)^2-2(x)(3)+(3)^2+36
y=x^2-6x+9+36
y=x^2-6x+45

Answer: Option C. y=x^2-6x+45
4 0
4 years ago
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