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2 years ago

What is the value of the expression below when w=8 x=4?

Mathematics

2 answers:

vodka [1.7K]2 years ago

6 0

W=8
X=4
9w +5x mean just substitute the corresponding values listed above in this equation
9(8)+5(4)
72+20=92

9966 [12]2 years ago

6 0

$\large\text{Hey there!}$

$\large\textsf{9w + 5x}$

$\large\textsf{= 9(8) + 5(4)}$

$\large\textsf{= 72 + 20}$

$\large\textsf{= 92}$

$\large\text{Therefore, your answer is: \huge\boxed{\textsf{92}}}}}\huge\checkmark$

$\large\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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How are exponents and logarithms related? give an example with you explanation

Soloha48 [4]

Exponents and logarithms are inverse functions, which means that exponents are the way to "undo" logarithms and logarithms are what you use to "undo" exponents. exponents tell you how many times you have to multiply a value and logarithms ask which exponent you need to use to get a specified value. exponential equations are used in a lot of scientific fields; for example, in biology, they're used to calculate the half-life of organisms. they can also be used to estimate the growth of a population. additionally, the richter scale, which measures the magnitude of earthquakes, uses logarithms.

6 0

3 years ago

The table shows information about the numbers of hours 30 children spent on their tablets one evening. a) find the class interva

Bogdan [553]

Answer:

a) 20<h≤30.

b) 26.17 hrs

Step-by-step explanation:

The missing table is shown in attachment.

Part a)

We need to find the class interval that contains the median.

The total frequency is

$\sum \: f = 30$

The median class corresponds to half

$\frac{1}{2} \sum \: f ^{th} - - - value$

That is the 15th value.

We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.

2+8+9=19

This corresponds to the class interval 20<h≤30.

Adding from the bottom also gives the same result.

Therefore the median class is 20<h≤30.

b) Since this is a grouped data we use the midpoint to represent the class.

The median is given by :

$\frac{\sum \: fx}{ \sum\: f}$

$= \frac{5 \times 3 + 15\times 8 + 25 \times 9 + 35 \times 7 + 45 \times 4}{30}$

$= \frac{785}{30}$

$= 26.17$

8 0

3 years ago

Read 2 more answers

How do I create the line graph?

IrinaK [193]

the top numbers is the number you start on (on the bottom) then you go up (as the second number under it) in your case $ then you put a dot where they connect hope that helps!

3 0

3 years ago

An economist for a sporting goods company estimates the revenue and cost functions for the production of a new snowboard. These

Vladimir79 [104]

Answer:

Between 1000 and 5000 snowboards will make the function AP(x) >0.

Step-by-step explanation:

Since x can only take possitive values, we have that AP(x) = P(x)/x > 0 if and only if P(x) > 0.

In order to find when P(x) > 0, we find the values from where it is 0 and then we use the Bolzano Theorem.

P(x) = R(x) - C(x) = -x²+10x - (4x+5) = -x²+6x - 5. the roots of P can be found using the quadratic formula:

$r_1,r_2 = \frac{-6 ^+_- \sqrt{6^2-4*(-1)*(-5)} }{2*(-1)} = \frac{-6^+_-\sqrt{16}}{-2} = \{1, 5\}$

Therefore, P(1) = P(5) = 0. Lets find intermediate values to apply Bolzano Theorem:

P(0) = -5 < 0 ( P is negative in (-∞ , 1) )
P(2) = -4+6*2-5 = 3 > 0 (P is positive in (1,5) )
P(6) = -36+36-5 = -5 < 0 (P is negative in (5, +∞) )

The production levels that make AP(x) >0 are between 1000 and 5000 snowboards (because we take x by thousands)

5 0

3 years ago

Problemas de razonamiento división de números decimales. Ayer Susana se fue de viaje a visitar a unos familiares. Recorrió 135,7

schepotkina [342]

Usando las relaciones entre velocidad, distancia y tiempo, se encuentra que ella condujo a una velocidad media de 90,5 km/h.

--------------------------

La <u>velocidad </u><u>es la distancia dividida por el tiempo</u>, por lo que:

$v = \frac{d}{t}$

Total de 135,75 km, o sea, $d = 135,75$
Llego en 1,5 horas, o sea, $t = 1,5$

La velocidad es:

$v = \frac{d}{t} = \frac{135,75}{1,5}$

División de decimales, o sea, seguimos multiplicando los números por 10 hasta que ninguno sea decimal:

$v = \frac{135,75}{1,5} = \frac{1357,5}{15} = \frac{13575}{150} = 90,5$

Ella condujo a una velocidad media de 90,5 km/h.

Un problema similar es dado en brainly.com/question/24558377

4 0

2 years ago