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4 years ago

(-11r+14+9r^3) + (3-8r^5+14r^3)

Mathematics

1 answer:

murzikaleks [220]4 years ago

3 0

-8r^5+23r^3-11r+17

Wasn’t Sure What It Was Asking So Hopefully That Works For You

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Find the GCF of 18xy and 32xyz<br><br> If you answer my question you will recieve 35 points

densk [106]

There is one 2 in common and there are "x" and "y" variables in common. Finally, the GCF of 18xy and 32xyz is 2xy.

7 0

4 years ago

Read 2 more answers

66×10^4 in standard notation

Vera_Pavlovna [14]

660000, just add 4 zeros onto 66.

8 0

3 years ago

-4x = -1/2(10x + 18)

frosja888 [35]

Answer:

x = -9

Step-by-step explanation:

-4x = -1/2(10x + 18)

Distribute

-4x= - 5x -9

Add 5x to each side

-4x+5x = -5x+5x -9

x = -9

5 0

3 years ago

Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable

bekas [8.4K]

Answer:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

$u=\frac{y}{x}$

Multiply both sides by x:

$ux=y$

Second step: Differentiate the substitution:

$u'x+u=y'$

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

$u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}$

$u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}$

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of $x^2$ so I'm going to divide top and bottom by $x^2$ :

$u'x+u=\frac{u+u^2}{3+u^2}$

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

$u'x=\frac{u+u^2}{3+u^2}-u$

Find a common denominator: Multiply second term on right hand side by $\frac{3+u^2}{3+u^2}$ :

$u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}$

Combine fractions while also distributing u to terms in ( ):

$u'x=\frac{u+u^2-3u-u^3}{3+u^2}$

$u'x=\frac{-u^3+u^2-2u}{3+u^2}$

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

$u' \frac{3+u^2}{-u^3+u^2-2u}x=1$

Divide both sides by x:

$\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}$

Reorder the top a little of left hand side using the commutative property for addition:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

The expression on left hand side almost matches your expression but not quite so something seems a little off.

5 0

3 years ago

Nicki Plans to attend a state university in two years. Thanks to girls from relatives and earnings from an afterschool job, she

Crazy boy [7]

Answer:

Step-by-step explanation:

Thanks to girls from relatives and earnings from an afterschool job, she has already saved $3700. If she's a seed in her goal of saving $150 per month, then if she saves for x months, the total amount that she would be have earned is

150x + 3700

1 year = 24 months

If she saves for 2 years, it means that the number of months for which she saved is 2 × 12 = 24 months. Therefore, the total amount

that she will have two years from now is

150 × 24 + 3700

= 3600 + 3700

= $7300

7 0

3 years ago