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MrRa [10]
3 years ago
10

Arnoldo needs to write this system in slope-intercept form. Which shows how he could do that? 3 x minus 2 y = 6. 0.4 (20 y + 15)

= x. y = negative three-halves x + 3 y = one-eighth x minus three-fourths y = three-halves x minus 3 y = one-eighth x minus three-fourths y = negative three-halves x minus 3 y = one-fifth x minus StartFraction 15 Over 4 EndFraction y = three-halves x minus 3 y = one-fifth x minus StartFraction 15 Over 4 EndFraction
Mathematics
2 answers:
Fofino [41]3 years ago
7 0

Answer:

The slope intercept form of 3x - 2y = 6 is y  = \frac{3x}{2} - 3

<em>In other words, y = three-halves x minus 3</em>

Step-by-step explanation:

Given:

3x - 2y = 6

Required:

Proper representation of the slope intercept form

To get the proper system that represents the given expression, we have to make y the subject of the formula.

Follow the steps below

<em>Step 1: Write out the expression</em>

3x - 2y = 6

<em>Step 2: Take 3x to the other side of the equation</em>

- 2y = 6 - 3x

<em>Step 3: Multiply both sides by -1</em>

-1 * -2y = -1 * (6 - 3x)

<em>Step 4: Write out result</em>

2y = 3x - 6

<em>Step 5: Divide both sides by 2</em>

\frac{2y}{2}  = \frac{3x - 6}{2}

y  = \frac{3x - 6}{2}

<em>Step 6: Split fraction</em>

y  = \frac{3x}{2} - \frac{6}{2}

y  = \frac{3x}{2} - 3

Hence, the slope intercept form of 3x - 2y = 6 is y  = \frac{3x}{2} - 3

<em>In other words, y = three-halves x minus 3</em>

kotegsom [21]3 years ago
4 0

Answer:

  y = three-halves x minus 3

Step-by-step explanation:

Subtract 3x from both sides of the original equation.

  -2y = -3x +6

Divide by -2

  y = 3/2x -3

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Estimate the area of Alberta in square miles. Show your reasoning
ella [17]

Answer:  About 278,250\ mi^2

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid  can be calcualted with the formula:

A_t=\frac{h}{2}(B+b)

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

 A_r=lw

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

A=\frac{h}{2}(B+b)+lw

Substituting vallues, you get:

A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2

Therefore, the area of of Alberta is about 278,250\ mi^2.

5 0
3 years ago
Can someone help me out with this
katen-ka-za [31]

Answer:

AB=4.41

Step-by-step explanation:

Use the cosine ratio, cosine=\frac{adjacent}{hypotenuse} . Insert the values:

cos25=\frac{4}{x}

Isolate x. Multiply both sides by x:

x*(cos25)=x*(\frac{4}{x})\\\\x*cos25=4

Divide both sides by cos 25:

\frac{x*cos25}{cos25}=\frac{4}{cos25}\\\\x=\frac{4}{cos25}

Insert into a calculator:

x=4.414

Round to the nearest hundredth:

x=4.41

Done.

5 0
3 years ago
The graph shown can be used to solve which of these systems of equations?
mrs_skeptik [129]

Answer: It is B

Step-by-step explanation:

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7 0
3 years ago
Pls help!!
erik [133]

Answer:

A

Step-by-step explanation:

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2 years ago
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Answer:

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