Answer:
The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
Step-by-step explanation:
In a random sample of 300 boards the number of boards that fall outside the specification is 12.
Compute the sample proportion of boards that fall outside the specification in this sample as follows:
The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:
The critical value of <em>z</em> for 95% confidence level is,
*Use a <em>z</em>-table.
Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:
Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
Answer:
Option b is correct 175
Step-by-step explanation:
n = 7
k = 6
3k -2 ------1
put k = 6 in above eq. for finding first term
a1 = 3(6) - 2 = 18 - 2 = 16
put k = 7 in above eq. for finding first term
a2 = 3(7) - 2 = 21 - 2 = 19
a3 = 3 (8) - 2 = 24 - 2 = 22
16, 19 , 22, ... //Arithmetic series formation
a1 = 16 , a2 = 19
d = a2 - a1 = 19 - 16 = 3 //Difference of first two terms
Using sum forumula for arithmetic series
sum = 
= 
= 
= 
= 
= 7 * 25
= 175
Answer:
Length = 90 inch.
width = 30 inch
Let width of the rectangle = x inch.
So the length = 3x inch.
Perimeter = 2(length + width) = 2 (3x + x) = 8x.
So,
length = 3x = 3(30) = 90 inch.
width = x = 30 inch
46%d+57%y=55%x42
x+y=42
Find y
x=42-y
46%(42-y)+57%y=23.1
19.31-46%y+57%y=23.1
11%y=23.1-19.31
11%y=3.79
y=34
The answer is D
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.
2. Where C(n, r)=
3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.
4. Or we could do this with the formula C(3, 2)=
5. C(8, 6)=
So there are C(8,6)=28 ways of chosing 6 out of 8 people to form the subcommittees. <span />
