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zhuklara [117]
2 years ago
15

The area of a rectangle is (16x^2 - 9y^2) square units

Mathematics
1 answer:
defon2 years ago
4 0
The area of a rectangle is (16x^2 - 9y^2 ) sq units

Since both terms are perfect squares, factor using the difference of squares formula,
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
a
2
-
b
2
=
(
a
+
b
)
(
a
-
b
)
where
a
=
4
x
a
=
4
x
and
b
=
3
y
b
=
3
y
.
(
4
x
+
3
y
)
(
4
x
−
3
y
)
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<img src="https://tex.z-dn.net/?f=8%20%5Cfrac%7B3%7D%7B5%7D%20" id="TexFormula1" title="8 \frac{3}{5} " alt="8 \frac{3}{5} " ali
IRINA_888 [86]

Answer:

Step-by-step explanation:

8 3/5 is already in simplest form.  You could write this mixed number as an improper fraction:

43/5

or as a mixed decimal number:

8.6

5 0
3 years ago
6.Find the smallest whole number 2645 by which it should be divided so as to get perfect square. Also find the square root of th
kondaur [170]

Answer:

Thus, 2645 needs to be divided by 5 to become a perfect square. Thus, the required smallest whole number by which it should be divided so as to get a perfect square number is 5 and the square root is √529= 23.

Step-by-step explanation:

8 0
3 years ago
What’s the value of x?
11Alexandr11 [23.1K]

Answer:

98 degrees

Step-by-step explanation:

m<H = 45, m<F = 53

180 = 45 + 53 + (180-x)

82 = 180-x

x+82 = 180

x = 98

3 0
3 years ago
Read 2 more answers
I need help with number 16!!! Anyone?
astra-53 [7]
67 is a prime number, and its ones digit is two less than the tens digit.
4 0
3 years ago
A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?
AlekseyPX

Answer:

The width of the sandbox is 42\frac{2}{3} \ ft.

Step-by-step explanation:

Given,

Area of the sandbox = 10\frac{2}{3}=\frac{32}{3}\ ft^2

Length = \frac{1}{4}\ ft

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

Area = Length\times Width

On substituting the given values, we get;

\frac{1}{4}\times w=\frac{32}{3}\\

By cross multiplication method, we get;

w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft

Hence The width of the sandbox is 42\frac{2}{3} \ ft.

5 0
4 years ago
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