f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0
tan2(x) + √3[tan(x)] - tan(x) - √3 = 0
Factor into
[-1 + tan(x)]*[√3 + tan(x)] = 0
which means
[-1 + tan(x)] = 0 and/or [√3 + tan(x)] = 0
Then
tan(x) = 1
tan-1(1) = pi/4 radians
For the other equation
[√3 + tan(x)] = 0
tan(x) = -√3
tan-1(-√3) = -pi/3
so that
x = pi/4 or -pi/3 in the interval [0, 2pi]
9514 1404 393
Answer:
(x, y) = (-1, -16) or (3, 0)
Step-by-step explanation:
Perhaps you want to solve the system of equations ...
- y = x^2 +2x -15
- y -4x = -12
Substituting the first expression for y into the second equation gives ...
x^2 +2x -15 -4x = -12
x^2 -2x -3 = 0 . . . . . . . . add 12
(x -3)(x +1) = 0 . . . . . . . factor
Solutions are the values of x that make the factors zero: x = 3, x = -1.
The corresponding values of y are ...
y = -12 +4x
y = -12 +4{-1, 3} = -12 +{-4, 12} = {-16, 0}
The solutions to the system are ...
(x, y) = (-1, -16) or (3, 0)
Answer:

Step-by-step explanation:
Complete question is given below
Add:-
ab-bc+ac,bc-ca+ab,ca-ab-2bc
We have to find the result after addition
Now, adding all expression
We get

Combine like terms then, we get


Hence,
Answer:
y = 3.5x - 12.5
Step-by-step explanation:
First, find the slope using rise over run (y2 - y1 / x2 - x1) with the 2 points:
(-2 - 5) / (3 - 5)
-7/-2
= 3.5
Then, plug the slope and a point into y = mx + b to solve for b:
y = mx + b
5 = 3.5(5) + b
5 = 17.5 + b
-12.5 = b
Plug the slope and the y intercept into the equation y = mx + b
y = 3.5x - 12.5 will be the equation