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stepladder [879]
3 years ago
11

In April, Phillipa rode

Mathematics
1 answer:
mina [271]3 years ago
8 0

Answer:

Month 1:  she rode 33.3 miles

Month 2: she rode 16.65 miles

Month 3: She rode 133.2 miles

meaning in Month 3 she rode about 4 times more then month one and about 8 times more then she did in month 2

Step-by-step explanation:

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The sum of two whole numbers is 84, and their positive difference is 18.What are the two numbers? Please help
Vlad1618 [11]

Answer:

Step-by-step explanation:

8 0
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yan [13]

Answer:

46

Step-by-step explanation:

The missing length is 10-4 = 6

Therefore perimeter = 5 + 6 + 8+ 4+13 +10

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3 0
3 years ago
Idk the answer can u help me
valentinak56 [21]

The answer is C) 67

Angle FGE is a right angle so it is 90 degrees and angle AGF is the same as CGD so it is 23 degrees.

Add angle FGE and angle AGF together (90 + 23 = 113) and subtract that by 180 (180 - 113 = 67)

3 0
3 years ago
The first three steps in determining the solution set of the system of equations algebraically are shown in the table. y = −x2 +
lianna [129]
You have a system of equations \left \{ {{y = -x^2+2x-9} \atop {y =-6x+6}} \right..

1. Substitude right side of second equation into the left side of the first equation: -6x+6=-x^2+2x-9.

2. Solve this equation:
 x^2-2x+9-6x+6=0, \\ x^2-8x+15=0, \\ D=(-8)^2-4\cdot 1\cdot 15=64-60=4,  \\ \sqrt{D}=2,  \\ x_{1,2}=\dfrac{8\pm 2}{2  } =3,5.

3. Find y:
for x_1=3, y_1=-6\cdot 3+6=-18+6=-12,
for x_2=5, y_2=-6\cdot 5+6=-30+6=-24.

4. The solutions of the system are: (3,-12) and (5,-24).
Answer: Correct choice is A.


7 0
3 years ago
Read 2 more answers
Lim x--> 0 (e^x(sinx)(tax))/x^2
Tom [10]

Make use of the known limit,

\displaystyle\lim_{x\to0}\frac{\sin x}x=1

We have

\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)

since \tan x=\dfrac{\sin x}{\cos x}, and the limit of a product is the same as the product of limits.

\dfrac{e^x}{\cos x} is continuous at x=0, and \dfrac{e^0}{\cos 0}=1. The remaining limit is also 1, since

\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1

so the overall limit is 1.

4 0
3 years ago
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