I was thinking that the answer could be
2.810; log3 21.903
OR
<span> 2.810; log3 55.2 </span>
So,<span> log5 of 92 is between 2.5 and 3 Correct answer is A</span>
Answer:
the first one is x=3
Step-by-step explanation:
Answer:
I think the answer might be 0.012
Step-by-step explanation:
Answer:
P ( 5 < X < 10 ) = 1
Step-by-step explanation:
Given:-
- Sample size n = 49
- The sample mean u = 8.0 mins
- The sample standard deviation s = 1.3 mins
Find:-
Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.
Solution:-
- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:
X ~ N ( u , s /√n )
Where
s /√n = 1.3 / √49 = 0.2143
- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:
P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )
= P ( -14.93 < Z < 8.4 )
- Using standard Z-table we have:
P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1
8% of 552 is 44.16. Look at the percent sign as a decimal and move it two places to the left, that'll give you 0.08. To find 8% of 552, look at it as 0.08 multiplied by 552. After you multiply you should get 44.16.
