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3 years ago

What number should Rihanna use for the height of the parallelogram if she uses 28 inches for the base

Mathematics

1 answer:

astraxan [27]3 years ago

6 0

Answer:

$Height = 7in$

Step-by-step explanation:

Given

See attachment for parallelogram

$Base = 28in$

Required

What is the height?

The opposite sides of a parallelogram are equal and the height is the distance between the parallel sides.

From the question, we have:

$Base = 28in$

Also from the question, the difference between the two parallel sides is 7in.

Hence, the height of the parallelogram in 7in

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Trapezoid QRST has two right angles. A 5-in.altitude can be drawn dividing QRDT into a rectangle and an isosceles right triangle

Vika [28.1K]

Answer:

The area of the trapezoid is 57.5 square inches

Step-by-step explanation:

we know that

The trapezoid QRST can be divided into a rectangle QRDT and an isosceles right triangle RSD

see the attached figure to better understand the problem

step 1

The area of rectangle is given by the formula

$A=((QR)(RD)$

we have

$RD=5\ in$ ----> altitude

$QR=9\ in$

substitute

$A=((9)(5)=45\ in^2$

step 2

Find the area of the isosceles right triangle

The area of triangle is given by the formula

$A=\frac{1}{2}(RD)(DS)$

we have

$RD=DS=5\ in$ ---> because is an isosceles triangle

substitute

$A=\frac{1}{2}(5)(5)=12.5\ in^2$

step 3

Adds the areas

$A=45+12.5=57.5\ in^2$

3 0

3 years ago

Read 2 more answers

yanalaym [24]

Answer:

3x + 2 = y

hope it was helpful

4 0

3 years ago

Find the distance between -2/3 and 4/3 on a number line

finlep [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

The bearing of Y from X is 63

zimovet [89]

Answer:

117°

Step-by-step explanation:

As per diagram:

∠NXY ≅ ∠XYZ as alternate interior angles since XN and YN are parallel and XY is transversal
m∠XYZ = m∠XZY = 63° since ΔXYZ is isosceles

Find the measure of ∠YXZ:

m∠YXZ = 180° - 2*63° = 54°

Find the bearing of Z from X:

m∠NXZ = m∠NXY + m∠YXZ = 63° + 54° = 117°

8 0

2 years ago

An equilateral ∆ has sides of length 16 cm. Find the length of an altitude.

inn [45]

The length of the altitude is $8\sqrt{3}$

Explanation:

Let ABC be an equilateral triangle.

It has sides of length 16 cm

Let AD be the altitude of the triangle.

We need to determine the length of an altitude.

Let AC = 16 cm and CD = 8 cm

Let us consider the right angled triangle ADC

Using the Pythagorean theorem, we have,

$AC^2=AD^2+DC^2$

Substituting the values, we get,

$16^2=AD^2+8^2$

$256=AD^2+64$

$192=AD^2$

$8\sqrt{3}=AD$

The length of the altitude is $8\sqrt{3}$

5 0

3 years ago