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Brrunno [24]
4 years ago
8

X is greater than or equal to 6 graph the inequality

Mathematics
1 answer:
Leni [432]4 years ago
8 0

it is 0,6 if its 6x

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Is this right if not please tell me the right answer
zhuklara [117]

Answer: 57% for the first and 41% for the second

Step-by-step explanation:

Treatment 1 consists of 40 people and 23 had improved health take 23 and divide it by 40 and you get 0.575 multiply that by 100 and you get 57% do the same for the second question and you get 0.416 multiply by 100 and you get 41%

8 0
3 years ago
Simplify, the following <br> The order of operations::::
mamaluj [8]

D) 93

5+10^2-3(12-6)

5+10^2-3(4)

5+100-3(4)

5+100-12

105-12

93

hopes this hepls

3 0
3 years ago
Read 2 more answers
HELP HELP PLEASE omgggg
Vlad [161]

Answer:

Step-by-step explanation:

There are 2 rays GF and GA

The line is AC

The Segment is CE. You could argue that GC is also a segment. I don't think it is the intended answer. As an answer, CE is much safer.

3 0
3 years ago
What is (-8) + 11 + (-5)? <br><br> -3 <br> 14 <br> -24 <br> -2
Semmy [17]
-8 + 11 = 3
3 + -5 = -2

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7 0
3 years ago
When drawn in standard position, an angle a has a terminal ray that lies in the second quadrant and whose sine is equal to 9/41.
Semenov [28]

Answer:

\frac{40}{41}

Step-by-step explanation:

We have the angle in standard post has a sine ratio of

\frac{9}{41}

This means the opposite side length of the corresponding right triangle is 9 units and the hypotenuse is 41 units.

Using Pythagoras Theorem, the adjacent side length can be found using:

{x}^{2}  +  {9}^{2}  =  {41}^{2}

This implies that:

{x}^{2}  =  {41}^{2}  -  {9}^{2}

{x}^{2}  =  1600

x =  \pm \sqrt{1600}

x =  \pm40

The cosine ratio is adjacent over hypotenuse.

=  \frac{ \pm40}{41}

Since we are in the second quadrant, the cosine ratio is negative;

=  -  \frac{40}{41}

3 0
3 years ago
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