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The minimum number of comparisons to find the smallest number from 5 integers is 4.
<h3>How to find the Smallest Integer?</h3>
Let the five numbers be a,b,c,d and e.
Let s be an integer
Comparison 1:
a and b will be compared first and the smaller number of them will be equal to s
Comparison 2:
Now, a smaller number between a and b that is s will be compared with c. Similarly, the smaller number of both numbers will be taken as s in the next comparison.
Comparison 3:
Likewise, s and d will be compared and a smaller number will be taken as s for the next comparison
Comparison 4:
Likewise, s and e will be compared and a smaller number will be taken as s for the next comparison.
After 4th comparison, s will be equal to smallest number of 5 integers.
Thus;
Total comparisons = 4
Therefore, the minimum number of comparisons to find the smallest number from 5 integers is 4.
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Answer:
200 + 6n
Do not know what you wrote as answer choices, but this is correct.
They charge a one time fee of 200 to start - this is the constant.
They also charge 6 per shirt, this gives the equation 6n.
Now, add the two terms.
You should get:
200 + 6n as the expression.
Some types of fallacy are:
- Argumentum ad Baculum
- Argumentum ad Hominem
- Straw man fallacy
- The fallacy of hasty generalizations, etc
<h3>What is a Fallacy?</h3>
This refers to the mistaken belief about something that is based on an unsound argument.
Hence, we can see that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept.
Read more about logical fallacies here:
brainly.com/question/4255659
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