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ella [17]
2 years ago
6

Area= Help me please :(

Mathematics
1 answer:
mr_godi [17]2 years ago
7 0

Answer:

Khan Academy.

Step-by-step explanation:

You can go on khan academy and search up "area and graphs." The videos should immediately pop up. there are also lessons if you don't want to risk getting your problem wrong. If you are still confused and do not understand please just comment and I will respond.

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What is the radius of a circle whose equation is x^2+y^2-10x+6y + 18=0
rjkz [21]

Answer:

Explanation:

We must write this equation in the form

(

x

−

a

)

2

+

(

y

−

b

)

2

=

r

2

Where

(

a

,

b

)

are the co ordinates of the center of the circle and the radius is

r

.

So the equation is

x

2

+

y

2

−

10

x

+

6

y

+

18

=

0

Complete the squares so add 25 on both sides of the equation

x

2

+

y

2

−

10

x

+

25

+

6

y

+

18

=

0

+

25

=

(

x

−

5

)

2

+

y

2

+

6

y

+

18

=

0

+

25

Now add 9 on both sides

(

x

−

5

)

2

+

y

2

+

6

y

+

18

+

9

=

0

+

25

+

9

=

(

x

−

5

)

2

+

(

y

+

3

)

2

+

18

=

0

+

25

+

9

This becomes

(

x

−

5

)

2

+

(

y

+

3

)

2

=

16

So we can see that the centre is

(

5

,

−

3

)

and the radius is

√

16

or 4

6 0
3 years ago
Eric had 13 tiles to arrange in a rectangular design how does Erics drawing show that 13 is a prime number
zimovet [89]
You just need to divide 13 and 2 and get 6.5.

3 0
3 years ago
С<br> 60 mm<br> 25 mm<br> What is the length of the hypotenuse?
Anestetic [448]

Answer:

65mm

Step-by-step explanation:

From the Pythagorean theorem, we can write it as sqrt(60^2+25^2) which is 65.

8 0
3 years ago
consider this quadratic equation x2+2x+7=21 the nuber of positive solutions to this equation are blank. the approximate value of
S_A_V [24]

Answer:

<em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>+</u></em><em><u>7</u></em><em><u>-</u></em><em><u>2</u></em><em><u>1</u></em><em><u>=</u></em><em><u>0</u></em>

<em><u> </u></em><em><u> </u></em><em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>-</u></em><em><u>1</u></em><em><u>4</u></em><em><u>. </u></em><em><u> </u></em><em><u>=</u></em><em><u>0</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>. </u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>x²</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>+</u></em><em><u>1</u></em><em><u>. </u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>4</u></em><em><u>+</u></em><em><u>1</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>(</u></em><em><u>X+</u></em><em><u>1</u></em><em><u>)</u></em><em><u>²</u></em><em><u>. </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>X+</u></em><em><u>1</u></em><em><u>. </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>+</u></em><em><u>/</u></em><em><u>-</u></em><em><u>√</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>X=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>+</u></em><em><u>/</u></em><em><u>-</u></em><em><u>√</u></em><em><u>1</u></em><em><u>5</u></em>

<em><u>X=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>+</u></em><em><u>3.872983346207</u></em>

<em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>2.872983346207</u></em><em><u>(</u></em><em><u>greate</u></em><em><u>st</u></em><em><u> </u></em><em><u>sol</u></em><em><u>ution</u></em><em><u>)</u></em><em><u> round</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>possible</u></em>

<em><u>X=</u></em><em><u>-</u></em><em><u>1</u></em><em><u>-</u></em><em><u>3.872983346207</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>=</u></em><em><u>-</u></em><em><u>4.872983346207</u></em>

6 0
3 years ago
What’s the answer?????!
stepan [7]

Answer:

0.58×0.90=0.522

Step-by-step explanation:

Im not really sure if it's right

3 0
3 years ago
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