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melisa1 [442]
3 years ago
12

Least common denominator 7/40 and 1/30

Mathematics
1 answer:
masya89 [10]3 years ago
6 0
The least common denominator is 120

21/120 and 4/120
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The area of a square poster is 59 in.² find the length of one side of the posterior to the nearest 10th of an inch
TEA [102]

area of a square = S^2

to find length of side take square toot of area

sqrt(59) = 7.68114

to nearest tenth = 7.7 inches

3 0
3 years ago
What is the solution set to the inequality (4x-3)(2x-1)20?
Fynjy0 [20]

The given question is wrong.

Question:

What is the solution set to the inequality (4x – 3) (2x – 1) ≥ 0?

(A) \{x| x\leq 3\ \text {or} \ x\geq 1

(B) \{x| x\leq 2\ \text {or} \ x\geq \frac{4}{3}

(C) \{x| x\leq \frac{1}{2}\ \text {or} \ x\geq \frac{3}{4}

(D) \{x| x\leq \frac{-1}{2}\ \text {or} \ x\geq \frac{-3}{4}

Answer:

The solution set to the given inequality is \{x| x\leq \frac{1}{2}\ \text {or} \ x\geq \frac{3}{4}.

Solution:

Given expression is (4x – 3) (2x – 1) ≥ 0.

Let us take the expression is equal to zero.

(4x – 3) (2x – 1) = 0

By quadratic factor, If AB = 0, then A = 0 or B = 0.

(4x – 3) = 0 or (2x – 1) = 0

Let us take the first factor equal to zero.

⇒ 4x – 3 = 0

⇒ 4x = 3

$x=\frac{3}{4}

Now, take the second factor equal to zero.

⇒ 2x – 1 = 0

⇒ 2x = 1

$x=\frac{1}{2}

So, $x=\frac{1}{2},x=\frac{3}{4}.

Now, write it in the inequality to make the statement true.

$x\geq \frac{1}{2}\ \text{(or)}\ x\leq \frac{3}{4}

Option C is the correct answer.

The solution set to the given inequality is \{x| x\leq \frac{1}{2}\ \text {or} \ x\geq \frac{3}{4}.

6 0
4 years ago
Plz help me answer plz
kkurt [141]
1 decade = 10 years

so 1 decade 8 years = 18 years

18 years - 9 years = 9 years

answer is 9 years
3 0
3 years ago
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Please help solve for x and y !! 5 x + y = 11<br> x - y = 1​
Nimfa-mama [501]

Answer:

x = 2 and y = 1

Step-by-step explanation:

A) 5x+y=11

B) x - y = 1.

(Solving by substitution)

B) x - 1 = y

A) 5x + (x -1) = 11. 6x-1=11. 6x = 11+1

6x = 12

x = 12/2. x = 2

B. 2 - 1 = y. y = 1

6 0
3 years ago
Triangle ABC pictured above has a right angle at C. If a=4.3 and c=9, find the measure of angle B. Round to the nearest tenth of
Cerrena [4.2K]
61.4596 degrees? I used law of sines
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