The process of releasing silver iodide into the atmosphere to stimulate rainfall is called:?

PLEASE HELP!!! 30 points

Leto [7]

D i believe i’m sorry if i am wrong :)

5 0

3 years ago

Read 2 more answers

Iron(III) oxide is formed when iron combines with oxygen in the air.

Alisiya [41]

Answer:

Mass = 9.58 g

Explanation:

Given data:

Mass of Fe₂O₃ formed = ?

Mass of Fe = 6.7 g

Solution:

Chemical equation:

4Fe + 3O₂ → 2Fe₂O₃

Number of moles of Fe:

Number of moles = mass/molar mass

Number of moles = 6.7 g/ 55.8 g/mol

Number of moles = 0.12 mol

now we will compare the moles of Fe and Fe₂O₃.

Fe : Fe₂O₃

4 : 2

0.12 : 2/4×0.12 = 0.06 mol

Mass of Fe₂O₃:

Mass = number of moles × molar mass

Mass = 0.06 mol × 159.69 g/mol

Mass = 9.58 g

8 0

3 years ago

Can someone plz help me

vodka [1.7K]

Answer:

ask google tbh that's a lot of work for 10 points

4 0

3 years ago

Explain the basic principles involved in X-ray crystallography. Include Bragg’s law in your explanation.

Artist 52 [7]

Answer:

Bragg's law is considered the case of diffraction that gives coherent and incoherent angles when the ray is scattered from the crystal lattice.

Explanation:

Bragg's law is considered the case of diffraction that gives coherent and incoherent angles when the ray is scattered from the crystal lattice.

The Bragg's law is used to determine the crystal structure by explaining the scattering process between the x-ray and crystal surface.

Bagg's law stated that when incident ray incident on the surface of crystal its scattering angle will be the same as incident angle when path difference is equal to the wavelength of ray. This leads to constructive interference.

4 0

4 years ago

If the partial molar volumes of the two components of a binary solution are VA 30 m2/mol and Vg 20 m3/mol and the mole fraction

gregori [183]

Answer : The molar volume of the solution is, $24m^3/mole$

Explanation : Given,

Partial molar volumes of component A = $30m^3/mole$

Partial molar volumes of component B = $20m^3/mole$

Mole fraction of component A = 0.4

First we have to calculate the mole fraction of component B.

As we know that,

$\text{Mole fraction of component A}+\text{Mole fraction of component B}=1$

$\text{Mole fraction of component B}=1-0.4=0.6$

Now we have to calculate the molar volume of the solution.

Expression used :

$V_s=X_A\times \bar V_A+X_B\times \bar V_B$

where,

$\bar V_A$ = partial molar volumes of component A

$\bar V_B$ = partial molar volumes of component B

$V_s$ = molar volume of the solution

$X_A$ = mole fraction of of component A

$X_B$ = mole fraction of of component B

Now put all the give values in the above expression, we get:

$V_s=0.4\times 30m^3/mole+0.6\times 20m^3/mole$

$V_s=24m^3/mole$

Therefore, the molar volume of the solution is, $24m^3/mole$

3 0

3 years ago