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Viktor [21]
3 years ago
10

What's the Molar Mass of O2? O 16.0 g/mole o 32.0 g/mole 1.0 g/mole O 2.0 g/mole

Chemistry
2 answers:
stiks02 [169]3 years ago
5 0
............:.................................

Elza [17]3 years ago
5 0
32.0 g/mol! Take the atomic mass off of the periodic table (16) and multiply by 2 since there are two oxygen atoms. So your answer is 32.0 g/mol.
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There are two naturally occurring isotopes of copper. 63cu has a mass of 62.9296 amu. 65cu has a mass of 64.9278 amu. determine
SSSSS [86.1K]
1) You need to use the atomic mass of copper.


You can find it in a periodic table. It is 63.546 amu.


2) The atomic mass is the weigthed mass of the different isotopes.


This is, the atomic mass of one element is the atomic mass of each isotope times its corresponding abundance:


=> atomic mass of the element = abundance isotope 1 * atomic mass isotope 1 + abundance isotope 2 *  atomic mass isotope 2 + ....+abundance isotope n * atomic mass isotope n.


3) The statement tells there are two isotopes so the abundance of one is x and the abundance of the other is 1 - x


=> 63.546 amu = x * 62.9296 amu + (1-x)*64.9278


=> 63.546 = 62.9296x + 64.9278 - 64.9278x


=> 64.9278x - 62.9296 = 64.9278 - 63.546


=> 1.9982x = 1.3818


=> x = 1.3818 / 1.9982 = 0.6915 = 69.15%


=> 1 - x = 1 - 0.6915 = 0.3085 = 30.85%


Answer:


Cu-63 69.15%;


Cu-65 : 30.85%
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7 0
3 years ago
I need to know the measurements of this to the appropriate amount of significant figures
igomit [66]

Answer:

[See Below]

Explanation:

I'd say 44 something. It's probably ml but I can't see what it says on the tube.

3 0
3 years ago
Juan Carlos placed 35 grams of ke into a dry, 200-gram container. The top of the container was attached tightly. When the ice wa
lianna [129]
Correct answer is D
8 0
3 years ago
1. Which of the following pairs of factors affects the solubility of a particular substance? (1 point)
Lina20 [59]
<h2>Question no 1:</h2><h3>Answer:</h3>

The correct answer is option A which is temperature and the nature of solute and solvent

<h3>Explanation:</h3>
  • The solubility of a substance is its ability to dissolve in a particular solution.
  • Solubility is highly dependent on the temperature and nature of solute and solvent.
  • It is directly proportional to the temperature. As we increase the temperature, the solubility of substantial increases but for the exothermic reactions, solubility is inversely proportional to temperature.
  • Solubility is absolutely dependent on the nature of solute and solvent, as polar solute and solvents have high solubility than non polar.
<h2>Question no. 2</h2><h3>Answer:</h3>

The correct answer is option B which is a large amount of solute.

<h3>Explanation:</h3>
  • A concentrated solution contains the maximum amount of solute which can be dissolved in the solvent.
  • For example, in water sugar solution concentrated solution will contain a large amount of sugar dissolved in water without the addition of heat.
  • In dilute solution, there is a small amount of solute.
<h2>Question no. 3:</h2><h3>Answer:</h3>

The correct answer is option B which is molarity × liters of solution.

<h3>Explanation:</h3>

Molarity of a solution is the total number of moles of solute per unit volume of solution.

Its formula is:

             Molarity = Number of moles of the solute/volume of solution in liters.

    A number of moles of solute =  Molarity × Volume of the solution.

So the number of moles of solute is equal to the molarity and volume of solution. Hence correct option is B.

<h2>Question no 4.</h2><h3>Answer:</h3>

The correct answer is option D. Molarity of the dilute solution = 0.81 M

<h3>Explanation:</h3>

Given data:

        initial volume = V1 = 225 mL = 0.225 L

        Initial molarity = M1 = 0.80M

        Final volume =  V2 = 1 L

        Final molarity  = M2 = ?

Solution:

It is the dilution of the stock solution and the formula is given below:

V1M1 = V2M2

M2 = V1.M1/V2

By putting values in the formula:

M2 = 0.225 × 0.8/1

M2= 0.18

So the final molarity of the solution will be 0.18 M. Hence the correct answer is option D.

<h2>Question no. 5</h2><h3>Answer:</h3>

The correct answer is option B which is supersaturation.

<h3>Explanation:</h3>
  • Colligative properties of the solution are the properties which are not dependent on the number of particles of the solute in the solution.
  • While supersaturation of the solution means the solution containing the highest number of solute particles dissolved in the solution.
  • Since supersaturation is dependent on a number of solutes, it is not a colligative property.
<h2>Question no 6.</h2><h3>Answer:</h3>

The correct answer is option B/C, "which disrupts crystal formation of the solvent".

<h3>Explanation:</h3>
  • Depression of freezing point is the colligative property of the solution.
  • Which the lowering of the freezing point of a solution by adding the solute.
  • The addition of solute disrupts the crystal formation in the solvent, as it disrupts the intermolecular forces between solute particles.
  • Hence option B and C are the correct options because both have the same statement.
<h2>Question no 7.</h2><h3>Answer:</h3>

The correct answer is option D which is 142.

<h3>Explanation:</h3>

<u>Given data:</u>

Volume of solution = 167 ml

Percentage of solution = 85%

The volume of alcohol =?

<u>Solution:</u>

Percentage of solution ( v/v) = volume of solute/volume of solution × 100

The volume of solute = percentage × volume of solution/100

By putting values in above formula:

Volume of alcohol = 85 × 167/100 = 141.95 ml

<em><u>Hence the correct answer is option D which is approximately 142(141.95).</u></em>

8 0
3 years ago
Read 2 more answers
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