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Bond [772]
4 years ago
11

During the lab, you measured the pH of common household items. Write net Brønsted equations that show the acidic or basic nature

of the following substances, given the pH. For polyprotic acids, only show one proton transfer. Remember that spectator ions are not included. (Use the lowest possible coefficients. Omit states-of-matter in your answer.) (a) native lime (calcium oxide) with a pH of 10.50
Chemistry
1 answer:
tamaranim1 [39]4 years ago
8 0

Answer:

CaO + H₂O ⟶ Ca²⁺ + 2OH⁻

Explanation:

CaO + H₂O  ⟶     Ca²⁺   +   2OH⁻

base    acid       conj. acid  conj. base

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Answer:

There are three covalent bonds existing between NH3. .

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3 years ago
Alkenes can be converted to alcohols by hydroboration‑oxidation. Draw the structure of the alcohol or alcohols formed in the rea
OLEGan [10]

Hydroboration-oxidation is a reaction which follow anti markonikov orientation.

The stereochemistry of hydroboration-oxidation follows syn-adition being a stereospecific reaction. That means that boron and hydrogen are added from the same side.  Then, when the oxidation occurs, the boron is replaced by an hydroxyl having the same geometric position.

6 0
3 years ago
The​ half-life of​ plutonium-241 is approximately 13 years. a. How much of a sample weighing 2 g will remain after 70 ​years? b.
Studentka2010 [4]

Answer: A) 0.0480 grams and B) 56.16 years.

Explanation: Half live is the time in which the amount of radioactive substance remains halve of its initial amount.

The formula we use for solving this type of problem is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount and N is the remaining amount of radioactive substance and n is the number of half lives.

n=T/t_1_/_2

where, T is the time and t_1_/_2 is half life.

A) from given data, N_0 = 2 g

T = 70 years

t_1_/_2 = 13 years

N= ?

n=\frac{70years}{13years}

n = 5.38

\frac{N}{2g}=(\frac{1}{2})^5^.^3^8

\frac{N}{2g}=0.0240

N = 0.0480 g

So, 0.0480 grams of the substance will be remaining after 70 years.

B) N_0 = 2 g

N = 0.1 g

T = ?

Let's first calculate the value of n for this.

\frac{0.1}{2}=(\frac{1}{2})^n

0.05=0.5^n

Taking log to both sides:

log0.05=nlog0.5

-1.301=n(-0.3010)

n=\frac{1.3010}{0.3010}

n = 4.32

Half life is 13 years, so we can calculate the time as:

n=T/t_1_/_2

T=n*t_1_/_2

T=4.32*13years

T = 56.16 years

So, it will take 56.16 years for the radioactive substance to decay from 2 g to 0.1 g.

8 0
3 years ago
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Increasing the frequency _________________ the wavelength. Group of answer choices decreases increases does not change
Lesechka [4]

Answer:

heightens

Explanation:

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