The bearing of point X <u>from</u> point Z is 285°
<h3>Calculating bearings </h3>
From the question, we are to determine the bearing of point X from point Z.
Consider the diagram attached
The bearing of point X <u>from</u> point Z is the measure of the angle from the North of Z in the <u>clockwise direction</u> to the line that goes to X.
That is,
The bearing of point X from point Z = 270° + 15°
The bearing of point X from point Z = 285°
Hence, the bearing of point X from point Z is 285°
Learn more on Calculating bearings here: brainly.com/question/22719608
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Answer:
x = -8
Step-by-step explanation:
x + (8/4) = -6
x × 4 + (8/4) × 4 = -6 × 4
4x + 8 = -24
4x = -24 - 8
4x = -32
x = -8
Explanation
We must the tangent line at x = 3 of the function:
The tangent line is given by:
Where:
• m is the slope of the tangent line of f(x) at x = h,
,
• k = f(h) is the value of the function at x = h.
In this case, we have h = 3.
1) First, we compute the derivative of f(x):
2) By evaluating the result of f'(x) at x = h = 3, we get:
3) The value of k is:
4) Replacing the values of m, h and k in the general equation of the tangent line, we get:
Plotting the function f(x) and the tangent line we verify that our result is correct:
Answer
The equation of the tangent line to f(x) and x = 3 is:
Answer:
y = 2x + 14
Step-by-step explanation:
Hope this helps!!!
First, you have to find the slope by using
In other words,
The slope is 2.
Then you plug the rest into point-slope form (you can use either of the points, I used the first one)
Remember that m is the slope.
Distribute the slope to the parenthesis
Isolate the y variable
Can you take a better picture because it’s hard to see where the line marks. or tell me the coordinates.
